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A0. B.#-@@#}(."6-@. 6."@6./@6.s/'6-@ "'6-@}/!6-@&/N-@@ !"D(Your time was:  SecondN B!+/ 6."}@6. 0/!@6.s :/F-@@ F(Your time was:  Minute SecondD/ 6-%N/ }6-%v/$3F:A8,%AV$F:A9,%@@D2:PROGMC B'g]$SC-F:A0,%AV$F:A1,F:A2,%AV$F:A3,O@1S 3F:A8,%AV$F:A9,%@}@D2:PROGMC B'f S0ੀ S0֠ـ`Lw*713Word Problems20Integer and Average Problems20Geometry20Quantitative Comparison 120Quantitative Comparison 220A }rithmetical Problems20Unit Conversions 20 20 20 } 20 20 20 } 20 20 20 } 20 20 20 } 20 20 }20 20 20 } 20Problems20Integer and Average Problems20Geometry20Quantitative Comparison 120Quantitative Comparison 220A &KAT @;@@,@6.) 26-@}6-@d,,@@ D2:CTRLFILEi @n @p6-@ s-@}x @(@ @,,@@ D2:CTRLFILE56-@6-@( }@5 @6-@ +(@ Word Problems+(@:-(@Integer and Average Problems}:(@"&(@Geometry&(@,7*(@Quantitative Comparison 17(@67*(@Qu}antitative Comparison 27(@@3&(@Arithmetical Problems3(@J/"(@Unit Conversions /(}@T@SC-F:A0,%AV$F:A1,F:A2,%AV$F:A3,O@1S 3F:A8,%A}V$F:A9,%@C D2:INITCTRLF B'f,@6.) 26-@A0001C375TA candy store which used to sell Tmints at 4 pounds for $10.00 raisedTthe price to 2 pounds for $7.50.} WhatTis the percent increase in price per Tpound? 133 1/3 240 350 466 2/3575 EDetermine the price per pound} Efor each: E 10.00/4 = 2.50E 7.50/2 = 3.75 EAmt. of increase = 3.75} - 2.50 = 1.25 E The % increase = 1.25/2.50 = 50%0002C409TColored beads are strung on a thread Tin a }repeating pattern of red, white,Tgreen, and blue; red, white, green, Tand blue. What is the color of the T75th bead?} 1red 2white3green4blue 5It cannot be determined from the5 information given EThe pattern repeats every 4 bea}ds.EIf there are 75 beads, then the Epattern repeats 75/4 or 18 times withEa remainder of 3 beads. The third bead}Eis the 75th. It is green. 0003D376TThere are four paths into a forest Tfrom point A to a lake at poi}nt B. TThere are five paths from the lake Tto point C at the other end of the Tforest. How many different routesT}could a bicyclist take from point ATto the lake and then on to point C? 142539420525EThe bicyclist has a choi}ce of 4 pathsEin and 5 paths out. Therefore, thereEare 4 * 5 = 20 different combinations.0004E471TStar}ting at point A, Bob hiked 3/5Tof the way to point B, then was drivenT9 miles, and then hiked 5 miles to Treach point B}B'DOS SYSB-AUTORUN SYSBk0PROGM BCTRLFILE BINITCTRL BNM7 B7M8 B=<M9 B@M10 BBM11 B>M12 BBBM13 B HELLO . How many miles did BobThike altogether?18212316421526ELet x = total number of miles E ESet up the equ}ation: E E 3/5x+ 9 + 5 = x E 9 + 5} = 2/5x E 14 = 2/5xE 35 = x E E35(total miles) - 9(miles driven}) = 26E(miles hiked)0005D545TA school student council needs $360 toTbuy food for a Thanksgiving party forTthe el}derly. If local businesses Tpledge one quarter of the whole amountTand the school offers to pay one thirdTof the r}emaining amount, what percentTof the whole amount does the councilTitself have to raise?120225 333 1/3 450566 2}/3 ESolve this problem in steps:E1/4 of 360 = $90(pledged by business);E 360 - 90 = $270 (remains)E1/3 of 270 = $90 }(pledged by school);E 270 - 90 = $180(remains to be raisedE by the council)E180/360 = 1/2 = 50% of to}tal amount0006E350TIf a person drives for 3 hours and 20Tminutes at 45 miles per hour, and 4Thours and 15 minute}s at 40 miles perThour, how many miles does he travel?11502170328043005320EFirst multiply to find the number of}Emiles traveled at each speed:E3 1/3 hours * 45 m.p.h. = 150 milesE4 1/4 hours * 40 m.p.h. = 170 miles ENow add: } 150 + 170 = 320 miles0007B363TIf 2 pounds of a candy that costs T$1.50 per pound are combined wit}h T6 pounds of a candy that costs $1.90Tper pound, what is the cost per poundTof the mixture?1$1.702$1.803$3.004}$3.405$7.60EFirst calculate total cost of the Ecandy: E2($1.50) + 6($1.90) = E $3.00 + $11.40 = $14.40} ENow divide to find cost per pound: E $14.40/8 lbs. = $1.80 per pound 0008B343TAn investor must ma}ke a 15% down pay- Tment on a $190,000 building she isTpurchasing. If she already put downT$8,000, how much must she st}ill payTfor the down payment?1$19,5002$20,5003$24,500 4$27,8005$28,500EFirst multiply to find total down pay-E}ment: .15 * 190,000 = 28,500 EThen subtract amount already put Edown: 28,500 - 8,000 = 20,500 }0009D477TOn a 360-mile car trip, Mr. Munk trav-Teled the first 1/3 of the trip at 40Tmiles per hour, the next 1/2 of }theTtrip at 45 miles per hour, and the Tfinal 1/6 at 60 miles per hour. HowTmany hours did the entire trip take? 142}6374859EFirst multiply to find the distanceEtraveled each part of the trip; thenEdivide by the miles per hour:E}1/3 * 360 = 120; 120/40 = 3 hoursE1/2 * 360 = 180; 180/45 = 4 hoursE1/6 * 360 = 60; 60/60 = 1 hourE EThe trip }took a total of 8 hours.0010B513TA seamstress receives $7.50 per hour Tfor a six-hour day and 1 1/2 times herT}hourly rate for any time over six Thours. If she received $58.50 for Ta day's work, how many hours did Tshe work}?17 1/627 1/538 1/1248 1/6 58 1/5 EFind the regular wages for one day:E$7.50 * 6 = $45 EFind amount of overti}me pay per hour:E1.5 * $7.50 = $11.25 EFind amount made in overtime that day:E$58.50 - $45 = $13.50 EFind hours }of overtime worked:E$13.50/$11.25 = 1.2 EFind out total number of hours worked:E6 + 1.2 = 7.2 = 7 1/5 0011C542}TIf one machine can produce 2,500Twidgets in 5 hours and another machineTcan produce 2,500 widgets in 3 hours,Tin how} many hours can the two machinesTworking simultaneously produce 2,500 Twidgets? 11 1/821 2/331 7/8 4458EIn 1 }hour, 1 machine does 1/5 the Ework; the other, 1/3 the work.ELet x = no. of hours needed by bothEmachines working s}imultaneously.ESet up the equation:E 1/5 + 1/3 = 1/xEFind least common denominator:E 3/15 + 5/15 = }1/xE 8/15 = 1/x ECross multiply: 8x = 15; thereforeE x = 1 7/80012D439THow many} liters of a solution that isT25% salt must be added to 10 liters ofTa 5% salt solution to obtain a solu-Ttion that is }20% salt?115220325430540ELet x = number of liters to be addedEand x + 10 = total number of litersE EChang}e the percents to decimals and Eset up the following equation: E .25(x) + .05(10) = .20(x + 10) EMultiply by 100: 25x} + 50 = 20x + 200 E 5x = 150 E x = 30 0013D378THow many hours w}ill it take to fill anTempty 65,000-cubic-foot tank if waterTconstantly flows into the tank at 1500Tcubic feet per hour} and flows out atT200 cubic feet per hour? 1526 1/2343 1/3 450565EFind out the net amount of water thatEremai}ns in the tank after one hour:E1,500 - 200 = 1,300 EThen divide 65,000 by that number toEfind the total number of hour}s: E65,000 / 1,300 = 50 0014D400TMr. Turk is now three times as old asThis son, Christopher. In ten yea}rs,TMr. Turk will be twice as old as hisTson is then. How old will Mr. Turk Tbe at that time? 120225330440545}ELet T = Mr. Turk's age and C = EChristopher's age ENow: T = (3)(C) ETen years from now: T+10 = 2(C+10) ESubstitu}te 3C for T: 3C+10 = 2C+20 E C = 10EIf C = 10, Mr. Turk is now 30. He willEbe 40 in ten years.}0015C283TA certain type of mortar mixture is toTbe made up of 25% gravel, 35% sand,Tand 40% cement. How many }pounds ofTthis mortar mix can be made with 8 Tpounds of cement? 18216320424532ELet x = number of pounds of mo}rtar mixEIf 40% of the mixture (x) is 8 pounds,Ethen .40(x) = 8 E x = 20 0016C463TMrs. La}rson can paint a room in 10Thours. Her husband can paint theTsame room in 8 hours. How many hoursTwill it take the husb}and and wife Tworking together to paint the room? 13 7/9 23 7/10 34 4/945 3/10 59 ELet x = total time ESet up} the following equation: E1/10 + 1/8 = 1/x EFind the least common denominator andEchange the fractions: E 4/}40 + 5/40 = 1/x E 9/40 = 1/x ECross multiply: 9x = 40 E x = 40/9 = 4 }4/9 0017E417TBill is older than Mary, but younger Tthan Sue. Jack is younger than Kevin,Tbut older than Sue. }Which of theTfollowing orders shows their relativeTages from oldest to youngest? 1J > K > S > B > M2K > J > S > M > B}3S > K > J > B > M 4M > B > S > J > K 5K > J > S > B > M E> will be the symbol for older than.EThe first sentence p}resents: S > B > METhe second presents: K > J > S EThe combination can only be: EK > J > S > B > M0018A}517TA jet and a prop plane take off onTdifferent runways from the same air-Tport at the same time but travel inToppo}site directions. The jet fliesTat 650 miles per hour, and the propTplane flies at 250 miles per hour. TAfter how many h}ours will the twoTplanes be 2,250 miles apart? 12.523.4635.62549510ELet x = hours traveled. DistanceEtraveled} by jet + distance traveledEby prop = miles apart. E(Distance = rate * time.) ESet up an equation: E 650x + 250}x = 2,250E 900x = 2,250 E x = 2,250/900 = 2.5 0019D434TOn a 217-nautical-mile voyage,} theTPinta averaged 9 knots for the firstT126 nautical miles and 7 knots forTthe rest of the voyage. How manyThours d}id the entire voyage take? 113214322427528EFind out how long it took to travelEthe first 126 mi. (126/9 = 14 ho}urs). ESubtract to find out the additional Enumber of miles (217 - 126 = 91). ENow divide to find out how long itEtoo}k to travel those milesE(91/7 = 13 hours). ETotal = 14 + 13 = 27 hours 0020B289TKatie is twice as old as Meg}an. SixTyears ago, Katie was four times as Told as Megan. How old is Katie now? 112218320424536ELet Katie = K}, and Megan = MENow: M = 1/2K ESix years ago: E M - 6 = 1/4(K - 6)ESubstitute 1/2K for M: E1/2K - 6 = 1/4K - }3/2 E 1/4K = 9/2E K = 36/2 = 18]pounds for $10.00 raisedTthe price to 2 pounds for $7.50.B0001B157THow many numbers between 15 and 55Tare each equal to 7 times an integer?1425364758EList the multi}ples of 7 between 15 andE55: 21, 28, 35, 42, 49 0002B322TIf the sum of 4 consecutive integer}s Tis 130, then the least of those Tintegers is 130231332433534ELet x = the least integer E ESe}t up the equation: E(x) + (x + 1) + (x + 2) + (x + 3)= 130E 4x + 6 = 130E  } 4x= 124E x= 31E 0003E383TIf A is an even integer and B is anT }odd integer, which of the followingTcould be an even integer? 1A + B 2A - B 32A + B 42A - B 5A - 2B EBy doubli }ng B in A - 2B, you make BEeven. An even integer subtracted Efrom or added to an even integer re-Esults in an even inte }ger. If you findEthis problem difficult, simply plugEin an even number for A and an odd Enumber for B and solve each eq }uation. 0004A200TThe average of positive integers A, B,TC, D, and E is what percent of theirTsum?120}2333404505100ETo average, divide the sum by theEnumber of items. The average in thisEcase would be 1/5 or 20% o}f this sum.0005D323TIf A, B, and C are consecutive inte- Tgers and their sum equals 189, what i}sTthe value of the largest of the threeTintegers? 154261363464574ELet x = the largest integerE ESet u}p the equation: E(x) + (x - 1) + (x - 2) = 189 E 3x - 3 = 189E 3x = 192E } x = 64 0006C219TIn 1978, a dock received 60,000 tonsTof cargo. If it received 90,000 tonsTi}n 1982, the average annual increaseTin tons received was15,00026,00037,500415,000530,000EThe increase was 30,00}0 tons over 4Eyears. 30,000/4 = 7,500.0007B213TWhat is the difference between theTgreatest and} least positive integersTbetween 100 and 500 divisible by 9?13822387339144825491EThe least positive integer is }108.EThe greatest is 495. The differenceEis 495 - 108 = 387.0008C304TA two-digit number has a }tens' digitTC and a units' digit D. What is theTproduct of this number and the numberT8 in terms of C and D?18C + 8D}28C + 80D380C + 8D 480C + 80D 5800C + 80D ED will be 8D and C will be 80C. IfEyou are unsure of how to do this pr}ob-Elem, substitute a number for CD and Emultiply by 8. 0009B228TWhat is the average of 4/9, 7/9, }6/9,T8/9, and 5/9?15/922/337/94556EIn order to average the fractions,Efirst add them:E4/9 + 7/9 + 6/9 + 8/9} + 5/9 = 30/9 EThen divide by 5 (the number of frac-Etions): E(30/9)/5 = 30/9 * 1/5 = 6/9 = 2/30010}A168TIf the sum of five consecutive inte-Tgers is 325, what is the average ofTthese integers? 165275310541255}325ESimply divide the sum by the numberEof integers (5): 325/5 = 65 0011E208TWhat is the av}erage of 2/5, 3/4, 7/10,Tand 3/2? 13/4217/20331/40443/60567/80EFind a common denominator and add theEfraction}s: E8/20 + 15/20 + 14/20 + 30/20 = 67/20 ENow divide by 4: E(67/20)/4 = 67/20 * 1/4 = 67/800012D }386TIf the average of the first twelveTintegers on a list is equal to theTaverage of the first eleven integersTon the!} list, then the 12th integer Tmust be equal to 1a positive number2a negative number3zero4the average of the fir"}st eleven 4 integers 5the product of the first eleven 5 integers EIf the 12th integer does not alterEthe avera#}ge, it must be equal to theEaverage. 0013B473TIf x is an integer between 5 and 13 Tinclusive, which $}of the following Tcould be the average of 3, 7, 9, 12, Tand x? 16.727.438.949.4511.1 EFind the sum of the lo%}west value of x Eand the other four numbers: E3 + 7 + 9 + 12 + 5 = 36 EThen, find the sum of the highest E&}value of x and the other four numbers:E3 + 7 + 9 + 12 + 13 = 44 EDivide each quantity by 5: E 36/5 '}= 7.2 E 44/5 = 8.8 EThe answer must be between 7.2 and 8.80014D190TWhat is the aver(}age of 1/5 and 1/9? 11/14 21/731/647/45514/45 EFind the common denominator and add Ethe fractions: 9/45 +)} 5/45 = 14/45ENow divide by 2: (14/45)/2 = 7/450015D255TOf the following, which is a com*}pleteTfactorization of a positive integer? 13 * 2 * 5 * 9 25 * 3 * 4 * 7 36 * 2 * 5 * 3 42 * 5 * 3 * 7 53 * 4 * 7+} * 2 EAn integer is factored completely whenEit is expressed solely as a product ofEprime factors. ,}0016A254TThe temperatures taken at five hourlyTintervals for a laboratory experimentTwere 42, 23, -8, -14, and --}18. What Tis the average temperature? 152-5304-21521EAdd the numbers and divide by 5:E42 + 23 + (-8) + (-14) .}+ (-18) = 25 E 25/5 = 50017C258TIf the average of a, b, c, d, and eTis /}16 and if f = 34, what is theTaverage of a, b, c, d, e, and f? 116218319420521EThe sum of a, b, c, d, and e equ0}alsEtheir average multiplied by 5: E16 * 5 = 80 EAdd the value of f and divide by 6: E80 + 34 = 114 E 114/6 = 191} 0018E290TWhat is the difference between theTgreatest and least of all two-digitTpositive integers, 2}each of whose Tdigits is a different nonzero Tmultiple of 4?188246344440536 EThe lowest two-digi3}t number each ofEwhose digits is a different multipleEof 4 is 48. The highest is 84. E84 - 48 = 36 0014}9E295TIf 20 students in a class of 30 aver- Taged 88 on a test and the other 10 Tstudents averaged 73, what is the 5} Tclass average on the test? 179280380.5481583EFirst calculate the total points: E20(88) + 10(73) = 1,760 + 6}730 = 2,490 ENow divide by the number of students: E2,490/30 = 83 (average score) 0020B506TThe ave7}rage of 20 students' testTscores is 78. When the 5 highestTscores are eliminated, the averageTof the remaining scores i8}s 72. WhatTis the average of the 5 test scoresTeliminated? 1100296392484575EDo this problem in steps: E 19}. 20 * 78 = 1,560 (total number ofE points scored) E 2. 15 * 72 = 1,080 (total of 15 E :} lowest scores) E 3. 1,560 - 1,080 = 480 (total of E top 5 scores) E 4. 480/5 ;}= 96 (average of top 5 E scores) ]h equal to 7 times an integer?1425364758EList the multi:0001E288TIf the area of a rectangle is 1 and Tthe base is 7 1/3, then the height Tof the rectangle is11222/3=}3741/753/22EArea = base * height. If the area = 1,Ethen the base 7 1/3 (22/3) times theEheight must equal 1. A fr>}action multi-Eplied by its reciprocal equals 1. TheEreciprocal of 22/3 is 3/22.0002C316TIf a recta?}ngle with a side of 9 has aTperimeter of 26, what is its area?126230336472581EIf one side = 9, then the other s@}ides E= 9, x, and x. Perimeter=2(base + ht).E 26 = 2(x + 9)E 26 = 2x + 18 E A} 8 = 2x E 4 = x EArea = base * height: 4 * 9 = 36 0003B235TWhat B}is one third of the perimeterTof a square with an area of 81?19 212315418521EIf the area of the square is 81, C} Ethen the base and height equal 9.EThe perimeter would be E2(9 + 9) = 2 * 18 = 36. EOne third of D}36 = 12.0004C298TIf one angle of a right triangleTmeasures 35 degrees, then the otherTangle mustE} measure135 degrees245 degrees355 degrees465 degrees575 degrees EThe angles of a right triangle totalE180 degreF}es.ETherefore, 90 + 35 + x = 180 E 125 + x = 180E x = 55 degrees G}0005C324TIf the three interior angles of aTtriangle measure 2x, 4x, and (x + 54)Tdegrees, then the smallest angleTmH}easures 118 degrees230 degrees336 degrees454 degrees572 degrees ESolve for x: E2x + 4x + x + 54 = 180 E I} 7x + 54 = 180 E 7x = 126 E x = 18 degrees EThe smallest angle would be 2x orE36 degreesJ}. 0006C203TIf one side of an equilateral triangleTis 5, what is the perimeter?15 square root 2 21031K}542052 square root 5 EAn equilateral triangle has three Eequal sides. If one side is 5, theEperimeter must then be L}15.0007B385TIf the perimeter of square q is twiceTthat of square z, then the area of q Tis M}how many times the area of z?122438412516EIf the perimeter of q is twice that ofEz, then each side of q must beN} twice Eas long as each side of z. Therefore Eif E 2 Ethe area of z is x * x = (x) , EO}then the area of q is E 2 2 2 E(2x) = 4x which is 4 times x . 0009D467TIf two P}sides of a right triangle areT1 and square root 2, which could beTthe length of the third side?11/2 2square root 23Q}2 4square root 3 53 E 2 2 2EUse the Pythagorean theorem:a + b =c ESquare root 2 coulR}d be either leg orEhypotenuse. Assume first that it is aEleg: E 2 2 2 E1 + square root 2 = c ES} 2 E 1 + 2 = c E 2 E 3 = c E squareT} root 3 = c 0010E365TIf a clock reads 12:20, which of theTfollowing is closest to the measure ofTthe angle betweU}en the hands of theTclock? 145 degrees260 degrees390 degrees4100 degrees5120 degreesEAt 12:20, the minute hand V}has moved E1/3 of the way around the clock. SinceEthe entire number of degrees in the Ecircle of the clock face is W}360, then Eone third of that amount is 120.E 0011B340TWhat is the area of a sector of a TX}circle of radius r if the sector isTbounded by a 45-degree arc?1pi/121 2 2pi r /8 2 2 36 pi r 3Y} 2 48 pi r 512 piE 2 EThe area of any circle is pi r . 45Edegrees is 1/8 Z}of the entire circleE(45/360). Therefore, the area of theE 2 Earc is pi r /8.0012E308TIf the c[}ircumference of a circle isT12 pi, then the area of the circle is1144 pi1 2 212 pi 2 2 36 pi 3 \} 2 4(12 pi) 536 piESince the formula for circumference isE2 pi r, the radius of a circle withEa circumference]} 12 pi is 6. Area of aE 2 2 Ecircle = pi r = (pi)(6 ) = 36 pi 0013C268TThe follow^}ing are the dimensions ofTfive rectangular solids. All are equalTin volume except 15 * 3 * 12 29 * 10 * 2 33 * 1_}0 * 5 46 * 5 * 6 55 * 4 * 9 EMultiply each set of dimensions to Efind the volume of each. A, B, D, and EE all eq`}ual 180. C = 150. 0014D249TWhat is the length in inches of a T216-degree arc in a circle whose a}Tcircumference is 30 inches? 18212 315418524 ELet x = length of the arcESet up a ratio: 216/360 = x/30E b} 216/360 * 30 = xE 216/12 = x E 18 = x 0015A318TIf a largc}e circular pizza is cut intoT24 equal pieces, each bounded by anTarc of the circle and two radii, whatTis the size of td}he arc that boundsTeach piece? 115 degrees224 degrees330 degrees436 degrees545 degreesEEach piece oe}f the pizza would be 1/24 Eof the 360-degree circle.E1/24 * 360 = 360/24 = 15 degrees.0016A241TOf f}the following computations for the Tvolume of a rectangular solid, which Tis the cloest to, but not greaterTthan, 175?g}17 * 3 * 8 26 * 9 * 238 * 5 * 4 49 * 7 * 3 58 * 6 * 4 EMultiply each equation: A = 168, EB = 108, C = 160, D = 1q}89, E = 192. 0017D310TIn a set of 16 cubic blocks, each Tblock has two green sides and one rr}edTside. How many sides of the entire setTare neither red nor green?116224332448560EA cube has six sides. Eacs}h cube has Ethree sides that are neither green norEred. Therefore, 16 cubes * 3 sides= 48Esides neither green nor red. t}0018D435TIf the perimeter of a square is 36, Twhat is the length of the diagonal ofTthe square? u}16293square root 90 4square root 1625square root 360 EEach of the triangles created by a Ediagonal in a square v}is a right Etriangle. Use the Pythagorean theorem:E 2 2 2 Ea +b =c . If the perimeter of theEsquare is 36, then eacw}h side is 1/4 ofE36, or 9. Therefore, 9 squared + 9Esquared = c squared; 81+81=c squared; E162 = c squared; square rootx} 162 = c. 0020C448TA rectangular holding bin is 16 feetTlong and 12 feet wide. If one ton ofTsand occupiesy} 32 cubic feet, how highTmust the sides of the bin be to holdT60 tons of sand? 14 feet26 feet310 feet414 feet52z}0 feetEFirst, determine the total amount ofEspace needed for sand to be stored: E60 * 32 = 1,920 cubic feet ENow dete{}rmine the size of the bin: E12 * 16 * x = volume E 192x = volumeENow set up the equation: 192x = 1,920 E |} x = 10 0008D240TA square with sides x and 2x - 4Twill have an area of1422x38x416}}5The answer cannot be determined5 from the information givenESince this is a square, all sides areEequal, so x = 2x ~}- 4 and x = 4E 2ENow solve for area: 4 = 160019D338TIn a rectangular coordi}nate system,Tthe lines with equations x = 2, x = 5,Ty = 2, y = -2 form a rectangle. WhatTis the area of the rectangle?}1628310412520EThe distance between the two x coor-Edinates is 5 - 2, or 3. The distanceEbetween the two y coor}dinates isE2 - (-2), or 4. The area is found byEmultiplying the two; 4 * 3 = 12.]ectangle is11222/3g0001A294T A B T T 3 2 2 3 T !} 4 + 3 4 + 3 1A > B2A < B3A = B4Relationship cannot be determined 5 EHere, simply compute the !}total of eachEand compare: 64 + 9 = 73E 16 + 27 = 430002C303T 8/!}x = 1/7T T A BT T 14/x 1/4 1A > B2A < B !}3A = B 4Relationship cannot be determined 5 EFirst, solve for x: If 8/x = 1/7 Ecross multiply to get x = 56. EThe!}n substitute the value for x: E14/x = 14/56 = 1/4 0003C300T A B T T 9!},747 rounded 9,731 rounded T to the nearest to the nearest T hundred hundred 1A > B2A!} < B 3A = B 4Relationship cannot be determined 5 ERound 9,747 down to 9,700; then roundE9,731 to nearest hundred, w!}hich also Eis 9,700. 0004B326T 3x + 7 = y T T A !} B T T 30x + 49 10y 1A > B 2A < B 3A = B 4Relationship cannot be determined !}5 ETo solve this, first determine the Evalue of 10y: 30x + 70 = 10y. ENow compare to 30x + 49. 30x + 49 Eis les!}s than 30x + 70, which is equalEto 10y. 0005D333T 12 > x > 8 T T !} A B T T 10x 90 1A > B 2A < B 3A = B 4Relations!}hip cannot be determined 5 EIf x is greater than 8 but less than E12, then 10x is greater than 80 but Eless than!} 120. 10x may or may not be Egreater than 90. 0006B284T 75% of x = 30 T T !} A B T T 25% of x 12 1A > B 2A < B 3A = B 4Relationship !}cannot be determined 5 ESolve for x: If 75% of x = 30 Ethen x = 30/.75 = 40ETherefore, 25% of x would be 10, whic!}hEis less than 12. 0007D367T A B T TThe average (arithmetical)!} y Tmean) of x and y 1A > B 2A < B 3A = B 4Relationship cannot be determined 5 EY may or may not be la!}rger than theEaverage of it and another number.ENOTE: If you are confused by abstractEproblems like this, substitute nu!}mbersEfor x and y. As different numbers areEused, the relationship changes. 0008A360T A !} B T T 3 2 T (1/2) (1/3) 1A > B 2A < B 3!}A = B 4Relationship cannot be determined 5 5 E 3 2 ESolve each: (1/2) = 1/8!}; (1/3) = 1/9ERemember that as fractions are raised Eto higher exponents, they become Esmaller values. !}0009A348T A B T T(45 - 28)/(9 - 7) (45/9) - (28/7)1A > B 2A < B3A = B 4!}Relationship cannot be determined 5 EYou should recognize that while A con-Esists of operations within one frac- E!}tion, B has two separate fractions Ethat can be reduced and subtracted. E E(45 - 28)/(9 - 7) = 17/2 = 8 1/2;E!}(45/9) - (28/7) = 5 - 4 = 1 0010A319TA sequence = 5, 11, 23, 47 ... T T A !} B T TThe next sequence item 94 1A > B 2A < B 3A = B 4Relationship cannot be determined 5 !}EIn this sequence, each number is oneEplus twice the previous number. Hence,Ethe next number in this sequence wouldEbe!} 47 + 47 + 1 = 95. 0011B196T x = -y T T A B T !}T x + y 1 1A > B 2A < B 3A = B 4Relationship cannot be determined 5 EIf x = -y, then x + y!} = 0 0012B275TThe average of a, b, c, d, e, Tand f is 14. T T A !} B T Ta + b + c + d + e + f 85 1A > B 2A < B 3A = B 4Relationship cannot be determined 5 EIf !}the average of six numbers is 14,Ethen the sum of those numbers isE6 * 14 or 84. 0013D377TOn a given!} day, 88% of seniors and 84%Tof juniors were present in school. T T A B T T !}The number of The number of T seniors absent juniors absent 1A > B 2A < B 3A = B 4Relationship cannot !}be determined 5 EIn order to determine the relation- Eship, you need to know how many Ejuniors and seniors atte!}nd the school.0014B414T A B T TThe sum of any two The sum of any twoT!}negative numbers positive numbers 1A > B 2A < B 3A = B 4Relationship cannot be determined 5 EThe sum of any !}two negative numbersEwill always be negative, while the sumEof any two positive numbers will Ealways be positive, !}and therefore Egreater. Try substituting numbers forEA and B to help understand this re-Elationship.0015C!}381T T A B T TThe number of odd The number of primeTintegers greater integers !}greater Tthan 4 but less than 1 but lessTthan 20 than 20 1A > B 2A < B3A = B4Relationship cannot be!} determined5 EThere are eight odd integers betweenE4 and 20(5, 7, 9, 11, 13, 15, 17, 19).EThere are eight prime int!}egers betweenE1 and 20(2, 3, 5, 7, 11, 13, 17, 19).0016A337T A B T TThe surf!}ace area The area of a circleTof sphere of of diameter 8 Tradius 4 1A > B 2A < B 3A = B 4Relationship canno!}t be determined 5 ESince a sphere is a solid object andEa circle is a linear figure, the sur-Eface area of the sphe!}re would be Egreater, even though both have aEradius of 4. 0017C395T A B T !}T 2 2 2T(x - y) 3x + x(-2x) + y - 2yx1A > B 2A < B 3A = B 4Relationship cannot b!}e determined5 ECarry out the operations of each andEcompare. E E 2 2E(x - !}y) (x - y) = x - 2xy + y E 2 2 E3x + x(-2x) + y - 2yx = E 2 2 2 2 2 E3x !}- 2x + y - 2yx = x - 2yx + y 0018B336T A B T T The number of Ten times the!}T seconds in an number of daysT hour in a year1A > B 2A < B 3A = B4Relationship cannot be dete!}rmined5 EThe number of seconds in an hour = 60Eseconds per minute * 60 minutes = E3,600. Ten times the number of day!}s inEa year = 365 * 10 = 3,650. 0019B388T A B T T The length of the!} 8T hypotenuse of a rightT triangle with legs ofT lengths 3 and 71A > B2A < B 3A = B4Relationship c!}annot be determined5 E 2 2 2 EUse Pythagorean theorem: a + b = c ,E 2 2 2 !} 2 E3 + 7 = c , 58 = c . Square rootE58 = c. Since square root 58 is lessEthan 8, 8 is larger. !}0020A442TA scale drawing is made of a circularTobject. T T A B T T !} The circumference The circumferenceT of the drawing of the drawingT when a scale of when a scale ofT 1 inch!} to 1 foot 1 inch to 2 feetT is used is used 1A > B 2A < B3A = B 4Relationship cannot be determined !}5 EIn A the scale is 1 to 12; in B the Escale is 1 to 24. The circumference Eof the drawing in A would be twiceEt!}hat in B. ] A B T T 3 2 2 3 T 0021B304T A B T T 9 8 T (-2) (-2) 1A > B 2A <%} B 3A = B4Relationship cannot be determined5 EThere is no need to work out the Eproblem. Remember that an ev%}en power Eof a negative number will be positive,Ewhile an odd power will be a negativeEnumber. 0022B%}204T A B T T 780,000/10 7,800 * 1001A > B2A < B 3A = B 4Relationship cannot %}be determined5 EDividing 780,000 by 10 resultsEin 78,000. EMultiplying 7,800 by 100 results inE780,000.%}0023C357T A BT Tz(x + y) + w(x + y) (x + y) (zw)1A > B 2A < B 3A = B %}4Relationship cannot be determined5 ERemember the distributive property ofEmultiplication. If the problem seemsEab%}stract, fit in numbers and work itEout: E ELet x = 2, y = 3, z = 4, and w = 5. EThen, 4(2 + 3) + 5(2 + 3) = 20 + %}25 =E45 and (2 + 3) (4 + 5) = (5) (9) = 45 0024B356T A B T T 2 2 %} 2 T 16 + 34 50 1A > B 2A < B3A = B4Relationship cannot be determined 5 ERemember th%}at you cannot simply addEdiffering bases before multiplying E 2 2 Ethem. Therefore, 16 + 34 =%} E 2 E256 + 1,156 = 1,412. 50 = 2,500. 0025A327T A %} B T T 15% of 150 7% of 75 1A > B 2A < B3A = B4Relationship cannot be determined5 EThere is%} a short cut to use here. ESince 150 is twice 75, you can reduceEA to 7 1/2% of 75. Since 7 1/2% ofE75 is greater than %}7% of 75, you canEanswer this question without doingEthe arithmetic. 0026D333T A %} B T T The perimeter One half of theT of a triangle perimeter of aT recta%}ngle 1A > B 2A < B 3A = B4Relationship cannot be determined5 EIn order to compare the relationship,Eyou must %}know the numerical values ofEthe dimensions (and therefore theEperimeters) of each figure. 0027B228T%} A B T T 11/23 23/47 1A > B 2A < B 3A = B 4Relationship cannot be dete%}rmined 5 ETo solve, divide the denominator ofEeach into its numerator: E E11/23 = .478 23/47 = .489 %}0029C347Tx and 54/x are both integers greater Tthan 2. T T A B T T %} 3 The least possibleT value of 54/x 1A > B 2A < B 3A = B 4Relationship cannot be de%}termined 5 EThe least possible value of 54/x forEwhich it and x are integers greaterEthan 2 is 54/18 = 3. Therefore,%} A and EB are equal.0030D460T p < q < o T T A B T T %} p -p/q 1A > B 2A < B3A = B 4Relationship cannot be determined 5 EA good way to handle a qu%}estion likeEthis is to substitute values for theEvariables and observe what happens. EBut be smart in choosing values t%}oEplug in. In this case, choose nega-Etive values. Take p = -3, q = -2. EThen B is greater than A. But if Ep = -3, q %}= -1/2. Then A > B. So theEanswer is D. 0031C407T A BT TThe number of even %} The number ofTprimes between 100 primes betweenTand 500 8 and 10 1A > B2A < B3A = B4Relationshi%}p cannot be determined5 EThe only even prime is 2, and it doesEnot occur between 100 and 500, so theEvalue of quanti%}ty A is 0. Neither 8 Enor 9 nor 10 is a prime number. So theEvalue of quantity B is also 0. So A=B.EThe right answer mu%}st be C. 0032B435T 2y = 6x + 5 T y = 3x + 5/2 T T A %} BT T x y 1A > B2A < B3A = B4Relationship cannot be determined 5 %}EYou do not always need to use all in-Eformation provided. Just inspectingEeither equation tells you x < y: toEmake u%}p 2 y's, you need more than E6 x's. So x is less than y. You do notEneed to find actual values for x and Ey to solv%}e this problem. 0033D287T 3x < 9 T 4y < 16 T T A B%}T T x y 1A > B 2A < B3A = B4Relationship cannot be determined5 EIf 3x < 9, then x%} < 3; if 4y < 16, Ethen y < 4. However, you still don'tEknow the exact values of x and y. 0034D298TT%}he sides of a triangle are of lengthsT3, 3, and x. T T A BT T 3 %} x 1A > B2A < B3A = B4Relationship cannot be determined 5 EUnless the triangle is equilateral inEwhich cas%}e x would equal 3, the rela-Etionship here cannot be determined.0035A390T A B%}T T The percent in- The percent de-T crease in the crease in theT price of a pro- price of a pro-%}T duct raised from duct decreased T $5.50 to $6.00 $6.00 to $5.50 1A > B2A < B 3A = B4Relationship canno%}t be determined 5 EThe increase from $5.50 to $6.00 isE.50/5.50 = 1/11 or 9% EThe decrease from $6.00 to $5.50 isE%}.50/6.00 = 1/12 or 8 1/3% 0036C450TThe interior angles of a triangleTmeasure x degrees, 4x degrees, andT%}7x degrees. T T A B T T The degree measure 105 T of the largest angle 1%}A > B2A < B3A = B4Relationship cannot be determined5 Ex degrees + 4x degrees + 7x degrees =E180 degrees (the d%}egrees in the sum ofEthe interior angles of any triangle).EIf 12x = 180 degrees, then x = 15 de-Egrees. The largest ang%}le is 7x orE7(15) or 105 degrees. 0037C432TIn triangle xyz, angle x = 77 degrees,Tangle y = 43 degrees. T %} T A BT TOne half the sum The degree measureTof the degrees in of angle z Tangle%}s x and y 1A > B 2A < B 3A = B 4Relationship cannot be determined 5 EThe interior angles of a triangle mustE%}equal 180 degrees. If 77 degrees + 43Edegrees + z = 180 degrees, then 120+z=E180 and z = 60 degrees. One half of Ex+y %}= (77 + 43)/2 = 120/z= 60 degrees.0038D280T A B T T Volume of a Volume of %}a T cylinder with cylinder withT a radius of 4 a radius of 7 1A > B2A < B3A = B4Relationship cannot b%}e determined5 EIn order to find the relationship, youEmust know the height of each cylinder.0039%}C368TIn a fair game of chance, a silverTdollar is tossed 25 times. T T T A B%} T T The chance that The chance that T heads will be tails will be T obtained 10 times obtained 1%}5 timesT 1A > B 2A < B3A = B 4Relationship cannot be determined5 5 EEach toss is independent. The chanceEo%}f getting heads or tails is equal inEeach toss. 0040D459TOn a particular math test, the averageTscore for girl%}s was 89 and the averageTscore for boys was 77. T T A B T T 83 T%}he average scoreT for the entire T group 1A > B 2A < B 3A = B 4Relations%}hip cannot be determined 5 EIn order to find the average for theEentire group you must know the numberEof boys and &}girls in the group. You Ecannot simply average the two sub-Egroup scores. 0028B349T 2 &} T x + 6y + 19 = 0 T T A B T T 2 T x + 6y &} 19 1A > B 2A < B 3A = B 4Relationship cannot be determined 5 E 2 2 &} ESolve x + 6y: x + 6y + 19 = 0; E 2 Ex + 6y = -19. EObviously, 19 is greater than -19. ]A > B 2A <$q0001E182T18/(2 1/4) = 1161/4 281/231/24458 EFirst convert 2 1/4 into an improperEfraction: 2 1/4 = 9/4 E*}Now invert and multiply: 18/1 * 4/9 ECancel the 9's and solve: 2/1*4/1 = 8 0002B206THow many *}numbers between 1 and 49 areTevenly divisible by both 2 and 57? 102439412524EOnly even numbers are divisible by*} E2, so find the even multiples of 5 Ebetween 1 and 49. They are 10, 20, E30, and 40.0003*}D251TIf a car can travel an average of 38 Tmiles per gallon of gasoline, how manyTgallons of gasoline will be needed t* }oTdrive the car 874 miles? 116219321423526EThis is a simple division problem: E874 miles/38 miles per gallon * }= E 23 gallons 0004E300TIf the two middle digits of 7,482 areTinterchanged, * }the resulting number is1the same as 7,482236 less than 7,482 336 more than 7,482 4360 less than 7,482 5360 more tha* }n 7,482 EReversing the middle digits of 7,482 Egives you 7,842. To find the differ- Eence, subtract 7,842 - 7,482 = 36* }0Emore than 7,482. 0005B317TIf a salesperson receives a 6% commis-Tsion on all sales, what com*}mission Twill she receive on sales of $24,300?T 1$145.802$1,458.00 3$1,450.80 4$14,580.005$145*},800.00 ETo find the amount of commission,Econvert the percentage to a decimal: E6% = .06 ENow multiply by the total *}sales: E.06 * 24,300 = $1458.000006C211TIf 21 * 4/a = 12, then a = 15 1/2 263747 1/2 58 ES*}olve for a: 21 * 4/a = 12 E 84/a = 12/1ECross multiply: 12a = 84 EDivid*}e both sides by 12: a = 7 0007B323TIf a family drives for 4 3/5 hours atTan average rate *}of 52 miles per hour,Thow far, in miles, is the drive? 1214.82239.23263.44291.25339.2 EFirst convert 4 3/5 hour*}s to a deci- Emal: 4 3/5 = 4 6/10 = 4.6 ENow multiply by the average rate: E 4.6 hours * 52 miles per hour = E *} 239.2 miles 0008B219TThe cost of 600 nails at $2.35 per 100Tis 1$12.702$14.*}103$127.004$141.00 5$1,410.00EThis problem is simple computation: EIf 100 nails cost $2.35, Then 600Enails cost s*}ix times that amount: E $2.35 * 6 = $14.10 0009B533TA couch sells for $632 when pa*}id in Tfull upon delivery. The same couch Tmay be bought on credit for $31.50 Tper month for two years. What is th*}eTdifference between the cost of the Tcouch when bought on credit and theTcost when paid for on delivery? 1$98.00 2*}$124.00 3$136.004$154.005$756.00 EFind out how much the couch will costEif bought on credit. There are 24 Emo*}nths in two years so multiply $31.50Eby 24: $31.50 * 24 = $756.00 ESubtract from that amount the cost ifEpaid for on d*}elivery: E $756.00 - $632.00 = $124.00 0010E469TIf an average of .001 of the 56,000Twidgets produce*}d daily at a factoryTare defective, how many widgets willTbe defective over an average two-weekTperiod, if the factory *}operates sixTdays each week? 156268322442805672EFirst find out how many widgets perEday are defective: E.00*}1 * 56,000 = 56 defective widgets E per day ENow multiply by the number of days E(2 weeks * 6 days pe* }r week = 12 days):E12 days * 56 widgets per day = E672 defective widgets per two weeks0012B174TIf Burt did 1,6*!}32 sit-ups in 8 hours,Thow many sit-ups did he average eachThour?1269220431,62941,84852,039ESimply divide to *"}find the answer: E 1,632 sit-ups / 8 hours = 204 0013E358TWhich of the following is equal*#} to 54?14 * ((6/2) + 10) 26 * ((4/2) + 4) 32 * ((10/2) + 10) 48 * ((6/2) + 4) 56 * ((6/2) + 6) EFirst perform the*$} operation in theEinnermost set of parentheses; thenEperform the operation in the outerEparentheses. Next, perform the *%}finalEoperation. E EA = 4 * 13 = 52; B = 6 * 6 = 36; EC = 2 * 15 = 30; D = 8 * 7 = 56;EE = 6 * 9 = 54*&}0014B403TIf a worker who earns $4.50 per hour Tand works 35 hours per week has $13.50Tin deductions subtracted f*'}rom his Tweekly paycheck, what is his weekly Tnet pay? 1$137.502$144.003$156.004$164.505$172.00EDo this pro*(}blem in two steps. First Efind the total weekly salary: E$4.50 per hour * 35 hours = $157.50 ENow subtract the total de*)}ductions:E $157.50 - $13.50 = E $144.00 0015A280TIf a box of 15**}0 pencils costs $14.00,Thow much will it cost to buy 1,950 Tpencils? 1$182.002$188.003$194.004$202.005$208.00*+}EFirst, find out how many boxes ofEpencils would be needed: E(1950/150 = 13 boxes) ENow, multiply by the cost per box:*,} E13 boxes * $14.00 = $182.00 0016C358TIf gasoline costs $1.24 per gallon andTa car averages 28 mi*-}les to a gallon, Thow much will the driver spend onTgasoline to travel 532 miles? 1$19.002$21.243$23.564$28.005*.}$29.36EFirst determine the number of gallonsEneeded: E532 miles/ 28 miles per gallon = 19Egallons neededENow, multi*/}ply by the cost per gallon: E19 gallons * $1.24 per gallon = $23.560017D283TA jacket that was originally*0} priced atT$28.50 is sold at a 40% discount. WhatTis the discounted price of the jacket?1$11.402$14.253$6.604$17.*1}105$19.10EFind the amount of the discount: E40% = .40 * $28.50 = $11.40 ENow subtract that amount from the Eorigina*2}l cost: E$28.50 - $11.40 = $17.10 0018E441TIf a salesperson earns $4.20 an hour Tplus a 4% commiss*3}ion on all sales, howTmuch would she earn during a forty- Thour week in which her sales totaledT$7,600.00? 1$168.002*4}$304.003$396.004$432.005$472.00 EFirst find the total hourly salary: E$4.20 per hour * 40 hours = $168.00 ENow f*5}ind the total commissions:E(4% = .04) E.04 * $7,600 (total sales) = $304.00 EFinally, add the salary and commis- E*6}sions: E$168.00 + $304.00 = E$472.00 (total earnings)0019E435TA taxi meter registers $1.15 for theTfirst ha*7}lf-mile and $.20 for eachTadditional 1/3 mile. How many miles Tis a trip that costs $3.35? 11122 5/6 33 1/643 2*8}/354 1/6EFind the cost of the trip minus theEfirst half-mile: E$3.35 - $1.15 = $2.20 EFind out how many 1/3-mile se*9}gments Eare in $2.20: $2.20/.20 = 11 EFind out how many miles are in elevenE1/3-mile segments:E11 * 1/3 = 3 2/3 mil*:}esEAdd in the first half-mile: E3 2/3 + 1/2 = 4 1/6 miles 0020D420TFour line segments have lengths (x+3),T(x*;} + 4), (2x + 1), and (2x - 2). If Tthe average length of the line seg- Tments is 12, how long is the longestTsegment?*<}11221334415516ESolve for x: E((x+3) + (x+4) + (2x+1) + (2x-2))/4=12ECross multiply:E(x+3)+(x+4)+(2x+1)+(2x-*=}2) = (4)12 E 6x+6 = 48 E 6x = 42 E x = 7 EFind the l*>}ongest segment:E(2x + 1) = 2(7) + 1 = 14 + 1 = 150011C325TWhen a certain number is divided by 4,Tthere is no r*?}emainder. When that sameTnumber is divided by 8, there is aTremainder. The remainder must be1122344657EIf the*@} number is evenly divisible by E4, yet not by 8, the remainder canEonly be 4 when the number is dividedEby 8. Try it w*A}ith several numbers suchEas 12, 20 28.]EFirst convert 2 1/4 into an improperEfraction: 2 1/4 = 9/4 E(;0001D186TA runner wins a mile race in 4:14. TWhat is the runner's time in seconds?11642214323442545284E.C}Convert to seconds:E4 minutes * 60 seconds = 240 secondsEThen add: 240 + 14 = 254 seconds000.D}2E202TIf in Zwanti weeks are ten days long,Thow many days would Zwen be on vaca-Ttion if she received a 3 1/2 Zwantia.E}n Tweek vacation?124225330433535EConvert to days: E(3 * 10) + 1/2(10) = E 30 + 5 = 35 .F}0003B362TIf 36 pamphlets can be duplicated in T15 minutes, how many hours will it Ttake to duplicate 1,00.G}8 pamphlets?142731.5414528EIf 36 pamphlets can be duplicated inE15 minutes, then multiply by 4 to findEout ho.H}w many pamphlets can be dupli- Ecated in one hour (4 * 36 = 144). ThenEdivide 144 into 1,008 to find how manyEhours th.I}e total duplication will takeE(1,008/144 = 7).0004E355TIf a family consumes an average ofT12 ounces of.J} meat per day, how manyTpounds of meat will the family consumeTin 15 weeks? 15 1/4228 1/2343 3/4 467 1/4 578 3/.K}4 ERemember there are 16 ounces in oneEpound. Therefore, 12 ounces equal 3/4Epound. E E3/4 * 7 days = 5 1/4 pound.L}s per weekE5 1/4 * 15 weeks = 78 3/4 total poundsE E 0005C380TTh.M}e volume of a cube with an eight- Tfoot length is how many times the Tvolume of a cube with a four-footTlength?1.N}22438412516ERemember the formula for volume of a E 3 Ecube is V = L . Substitute the given Efig.O}ures; then determine how much Elarger one is than the other by Edividing: E 3 3E .P} 8 = 512; 4 = 64E 512/64 = 80006A320TMr. Flick has to wait 3 1/4 hours forThis plane. Ms..Q} Galvin has to wait T5 2/3 hours for her plane. How muchTlonger, in minutes does Ms. Galvin Thave to wait? 1145 21.R}6531954275 5340EConvert the hours to minutes: E 3 1/4 * 60 = 195 minutesE 5 2/3 * 60 = 340 minutes.S}E 340 - 195 = 145 minutes 0007D316TIf a store sells 72 quarts of milk Teach day, how many gal.T}lons will it Tsell in 20 days? 1182903180436051,440EFirst, convert the daily number ofEquarts to gallons: E.U}4 quarts = 1 gallon E72/4 = 18 gallons per dayENow multiply by the number of days: E18 gallons * 20 days = 360 gallons .V}ofE milk in 20 days0008C362TIf a steel girder weighs 380 pounds Tper cubic foo.W}t, what is the weight,Tin pounds, of a steel girder 10 feetTlong, 1 foot wide, and 2 feet thick?138023,80037,6004.X}38,000576,000EFirst, find the number of cubic feet Ein the girder (L * W * H = Volume):E1 * 2 * 10 = 20 cubic feetE.Y}Now multiply by 380(the number of Epounds per cubic foot): 20 * 380 = E7,600 pounds0009C338TIf.Z} planet Franquil has a day 28 hoursTlong, how many of our 24-hour daysTwould there be in a Franquilian 7-dayTweek? 17.[} 5/62838 1/648 1/358 5/6EFind out how many hours make up oneEFranquilian week (28 hours per day * E7 days = 196.\} hours). Then divide 24Ehours into the total number of hours Ein a Franquilian week (196/24=8 1/6). 001.]}0A512TOver the last six years the price ofTmilk has risen from 29 cents a quartTto $1.88 a gallon. What was the aver-.^} Tage annual increase in the price of aTgallon of milk? 112 cents218 cents329 cents454 cents572 centsEFirst, ._}figure out how much a gallon ofEmilk cost six years ago (29 cents perEquart * 4 = 1.16 per gallon). NowEsubtract that c.`}ost from current cost Eof a gallon (1.88-1.16 = 72 cents). ToEfind the average, divide the totalEincrease by the number.a} of years (72/6 E= 12 cents per year average increaseEper gallon). 0011E163TIf 6 blips equal 1 blop and 5 blop.b}sTequal 1 blap, how many blips equal 4Tblaps? 1202243304605120EEach blap equals 30 blips; thereforeE4 blaps.c} equal 4 * 30 blips = 120 0012E429THow many seconds less would there beTin a week if the week .d}were 6 days longTand there were 25 hours in each day?13,600286,4003604,80041,209,600564,800EFirst find out how .e}many seconds Ethere are in one week (60 secondsE* 60 minutes * 24 hours * 7 days = E604,800). Now find out how .f}many Eseconds in the proposed week E(60 seconds * 60 minutes * 25 hoursE* 6 days = 540,000). Now substract .g} E(604,800 - 540,000 = 64,800)0013E268TIf sand weighs 18 pounds per cubic Tfoot, what is the weight .h}in poundsTof a load of sand 12 feet * 10 feet *T9 feet? 11,080 210,800315,660417,840519,440 E12 * 10 * 9 = 1,.i}080 cubic feet.E18 pounds per cubic foot * 1,080 =E 19,440 pounds. 0014D395TT.j}he volume of a cube with sides that Tare 18 inches long is how many timesTless than the volume of a cube with Tsides .k}that are 9 feet long? 132938142165729EChange 18 inches to 1.5 feet. (You canEuse 3/2 feet instead.)EThen find.l} the volume of the cube E 3 EL = 1.5 * 1.5 * 1.5 = 3.375 cubicEfeet. The 9 ft. cube has a volume of E729 cubic feet.m}. Now divide the smallerEinto the larger (729/3.375 = 216). 0015E234TIf 23 airplanes land at an airport Te.n}very hour, how many airplanes landTthere in one week? 11682312355142,18453,864EFind how many planes land in one.o} dayE(23 * 24 hours = 552 planes per day). E552 planes * 7 days = 3,864 planes Eper week.0016B.p}336TIf a company sells 386 flanges in anTaverage week, how many dozen flangesTdoes the company sell in one year? 184.q}4 1/221,672 2/335,492 48,312 1/3 520,000EFirst multiply the number of flangesEsold each week by the number of wee.r}ksEin a year (386 * 52 = 20,072 flangesEper year). ENow to find how many dozen, divide by E12 (20,072/12 = 1,672 2/3).s}. 0017A333TIf Charlene drinks 12 ounces of milkTeach day, how many gallons of milk Twill she drin.t}k in one year (365 days)?T(Round off to nearest gallon.)134239342454568EThere are 32 ounces in one quart. E12.u} ounces = 3/8 of one quart, or 3/32Eof one gallon. Multiply this by theEnumber of days in a year (3/32 * 365 =E34.2 gal.v}lons). Round off to 34. 0018A575TIf over the last seven years the priceTof cola has risen from $1.14 p.w}er six-Tpack to $2.08 per eight-pack, what isTthe average annual increase in the Tprice of cola per bottle?11 cent.x}23 cents35 cents47 cents5The answer cannot be determined from5 the information given EFind the cost of a bottle.y} of cola Eseven years ago, and today ($1.14/6 =E19 cents; $2.08/8 = 26 cents). Now Efind the difference in cost between.z}Eseven years ago and today (26 cents - E19 cents = 7 cents). To find the Eaverage, divide 7 cents by the number Eof y.{}ears (7 cents/7 years = 1-cent- Eper-year increase).0019C488TIf Ms. Myslis has to wait 40 minutesTfor her trai.|}n and Mr. Kolberg waits T180 minutes for his train, how muchTlonger in terms of one day does Mr.TKolberg have to wait? .}}11/10 29/14437/7241/755/36EFirst find out how many more minutesEMr. Kolberg waits for his train E(180 - 40 = .~}140 minutes). Now in termsEof a day, find out the number of Eminutes in one day (60 minutes * 24Ehours = 1,440 min.}utes in one day). ENow find out what part of one day 140Eminutes represents (140/1,440 = 7/72Eof a day). 0020E.}353TIn a certain nation, the system ofTcurrency includes womps, wonks, andTdinks. If one wonk equals 20 dinks Tand 5 .}wonks equal one womp, how many Tdinks equal 3 womps? 1422036041005300EIf there are 20 dinks in one wonk,Ether.}e must be 5 times that number inEone womp (5 * 20 = 100). If there areE100 dinks in one womp, there must beE300 dinks i.}n 3 womps (3 * 100). ]e in 4:14. TWhat is the runner's time in seconds?11642214323442545284E,& 1?AWA@ B'` SAT1 +A2}1AAR@-@@(( --@@ 2( 2} 7-@@<( A-@@F( K-@@P( 2} U-@@Z( _-@@a( n-@A  +2}'AR@'A'@'@@9--@@-(COPYRIGHT (C) 1984 2}<-@@<("by Harcourt Brace Jovanovich, Inc..-@@.(All rights reserved.-@@2}''(No copy of the computer program:-@@:( embodied in this diskette may be4-@@4(ma2}de without prior written"8-@@8(permission from the publisher.,)-@@ )(VERSION 1.1A AT2}%D:PROGM2 #B'd!-AVAg%"+/ 2#N;@,"6. h  \`B67@<@,.>:Ab2},N6-?:C:,,00165,16,41,127,133,16,141,14,210,108,96,228$SC-F:A0,%AV$F:A1,F:A2,%AV$2}F:A3,O@1S 3F:A8,%AV$F:A9,%@@D2:HELLOC B'f+A0k