@L|}6CD l0C)HCC WhL/h `CmCDiD`  R@P1  Y0@R !L` D  C D     )16CS S)  C)D1 p p 0 C9DI pCDL~CiCDiD` D  C D     )16CS S)  C)D1 p p }0 C9DI pCDL~CiCDiD` DD˙` d J)L !}D L(( LL()  L| L( S LH 0p n   } CY?  q  L L  ` ) } `A! d߰")-݆ "  $G@LLL&0") $G% }H0 3S8`G ȱG ȱG   Gȭ Gȭ GG}GHiH8(()) G$H% `(0 })8` d)L ݆ & LGȘ ݆LL d  ! LL d)N>Q  HH) }  hyhyB q L> Lm JJ  Ln*` dB%'}8  H H` 1 { LL   !L     Hh SY?  q  1L}  !? S   q 1 L   Ll  Lg E`L   !L)  q 1L}) `L0AM݊L݉ ML  N݆LLLNLMLHG!@}1F GȱGLLEEȩÑEȑEEȑE Ed E7EȩE  q} L !,0,0SGɛ L 1 !L EHEh W G gLLSROTCES EERF } G) *Gȩ GȽG GȌd q q G`  8   0G  `D}CEDC0X:Ȣ Y ȱC* ? 0.. , 0%n ?A[ 0 : L`L  `, 0`Y}`piH n0)բY? 08`0 }  0$L GGȽG L `8L`L}8`  05G)݁,G)ȱGȱGHh0})Hh` B! 8`8iOiLE`}E8FEh( l0`ɃLL L8^~jj8jHi hEEEiEȱEiE` dTE} H8EEȱEEȩEh J E8   . m  i`LI!)E1FR}1LJ舩9GIH`LJJ`HGHh l`} S gL   8 rii `дCDCG W  }C  Lq` X٨`DOS SYS IIIIIIIIIIIIIIIC`0 ߩ0}}}  |||DDOS DOSDOS SYS }}}}}CDOS SYSL,DUP SYS } 0`BDELV !B !}`LVUQ   ]   TU J ]L!T# #      TU "} L ? .  t`GBJ V~DEHI B V0dV#}QDEHI VF9 ,0 ,0 s0hhL  L` H hDHEh$}DEL8HI   0 HI,0 0  9 .G VLO%},0 L4*IJ`llD1:AUTORUN.SYSNEED MEM.SAV TO LOAD THIS FILE.D1:MEM.SAV J y08 B|DEHI&} V0 0`B;DELV䌚 !B y`@ʆ v s? F0Ξ05: [ BDEHI'} VY8 B V  @  /DE `E:D1:DUP.SYSERROR-SAVING USER MEMORY ON DISKTYPE Y TO (}STILL RUN DOS B;DE J V (` 9 V⪍ ઍ  -)}LLu DEHILV 9 .l 9 .l  `` s$B VBH*}I|DE V BLV nB,DE J V* \*` B V BLVDEHI BLVL+}1u H232435; 1 ;  hh@2 e1i1LHҍ 00) 08 109hh@ Ҡ2e,}1i1232435ޥ<<8P}6 7M@"M j6 B VB JKwD6E V6l8.}E:888687 m676泩6ҭ8888m8m680ƱƵ/}쥵21L0l8>D5$@@@I@@$@@@$0}@ $ @ H@ @$B@B @@! A 1}AAB!!  @ "@D   @@ @2}$!$"@H BA3} I$$I$  @ @ @ $@ $H4}B  @$@ A@ $$@$ H5}HI      @H$ @@H   6}$ B$ @$H  @B$! UUUUUUUH@I7}$ @HHI@$$ $ @  @  H  $B@ HB!$ 8} @HI $@ @ H @ H$ 9} ! @ B!  @ $!H! @:} $ $H$$ $I  $@@$@  $  @ $ $@!$$! ;} @ "@@@ @ B@ @I@  <}@ @@DxLDL*EL3Q ?=}OSS BASIC A+ version 3.04COPYRIGHT (C) 1981 OSS LZ LR=Α ȩD H ȱ D h =D!>} ɛ``RUN "l  !… D `dD` DL*El E: FDL*E FD tȊ O ?}Oȩȩ D" Qh@@jIDˢ tD i/D i t t t "u tLD Qک]O O@}L~P'*ɛ")"a{)_ ȱ)" DЪ򅟅 F H ۤ򄨱ɛ $0LFLjE H A}۩J I H G5ɛȑ @膔S Hɛ HɛК P Q8 IȢ B}O H Qh P$P* P8孨客 P$ cLjE {cLjEL~P P FLjE QH Qh P` ؐ0 1UC}0Ԅ HLH G0* fGLGY GLG8eHeHLyG GH GH hhHH`D}hhL3GLh`ʆL3G G0 G GѰşL3G` G`E} 7hh*HLHLyG G``LhLELHF ۥųNϢ I(iŰII8` H`F}8` ۥ DI% 7H0 DI ې$$ 8`$ (ȩ@҅ҥ򄬥 I M ILH8򨢄 OG}Ӥ򈦬ʽʈ򈱗  O池$PƬ0 H`LhA[`8` ۥ ؐ` HԑH}` ۤ"8` H Hɛ " HLI嫤`毦򤪱').Q h( ei`I}8`Ūݱ08J}K}L}M}N}S}B'DOS SYSB}-AUTORUN SYSBGO B<PQINFO BPQMENU B9 PQPROB6 B!FPQCALC B9gPQPROB5 B1PQPROB7 B;PQPROB8 B8PQPROB9 T}U}V}W}O *D:GO`STRX}8ee Lh8Y}ueeeee褢 ƚƜ`8IȄ墅8夕Z}墅褢`朱` sg[ {l ci] {l {lğȱȄ PLP LQHMQH`0 D [} Q QLfLfLgEš Š` Q QLPei```` tLq t  ! LN"\}Ș` hQQ\blVbf deNeeeg6Qg n=e[Zf:fV[[f,f6fDmlm[nJnSnjmgD[[][\ [eefg]nn[bGnoUnnbQ"Q"]}mmnnmoqq*qSpq pqp]q^qfss_s>qrss[pVbhTgTpTTwT~TZTFT4T=TOTTTTTRU;hhTgTpTTwT~TTfTXUUFUBU;UBU9XX^}YXXX=XsX[ZNZDXTZ:YX^ZlZXZbZvTYYXsp/p3p7p;qqrhob9pW R R VSLRSJJJJS)Ŭ  RLR_}LR`8 QHQH`Ȅ`樱0C`ȱȩ"ȱօȘuԩׅu՘e֨҆ӄ` S` `}S$҅jeԨe` h檥 ũ ґ`Lh |S0`Lh |R SL1U qS` hƪ ҈` |SԤ` S La}S |RLS Sґ` & &ee`̪UfNCb} S ULVS S ULVS S "ULVS S (ULVS SILVS` U0KIB U=@ U0;4 U0/-0 U0&) U$ S% S c} S@Ԅբ֠ HڅLVS S0 SHH Shh` TըLEX T%ը%LEX2LW S U` fڰ` `ڰ ` ڰ` d}(۰` h !w` h氤hhLR@Ű ư S0#ԅ Sԅ0 S$P`fҰ hאְ菱ِ祗ذ W W We}Ԥ W W$ҥ ҥեLVSȄLVS VV VV8 S ҅Ҥ٥LV֤צưĘ0f}ŗ*8֪א 7SeԥeLVS h SԤ` ~V R V VSLfV` R Rʊ )` S0g}, S) ԅՅLV S` 7SԅՅօׄ 4S ݦפ֥) ٤؊ţĢeԨeժ8包卅h}8墅8墅8墅 dPH) %S8Ԩժ(א ֐ֆץ SґheԅԥeՅե) i}8֥8`8إ8`&&ee`J uڕv` 4S 4S 0X 0X( j}``(`ε` 4S֤ׅԄ ٩҅LVS SLEX S8吅ԭ呅LIX S " h u k} "u h 4SLEX 4SLIX S إԥՠȱ)Ȅ S 1Uԍթԩׅ֩өLVS SԅܥՅ 4S 4Seԅl}eՅ$8待֥必א8ⅾㅿLT.ԅՅڦ0$ LaYեƾƿ0LBY8m}檥e܅Ԙe݅LIXƠY S ҄Ԭ ҄ (ULVSBU6 S)LVS YLIX Sƺ0 HHLY*Hl S ZLVS)8n}?Ք Fک U`L S /u?: S 9u50 S u+& S ް! S ް S ݰ  S mvLVS h So} 0LT0)ԥ)8@0ܢ8ʈJHH ްh "U ݰ hԅЉ hħ` |Rp}j h8*0/0ֆׄ0ۄ؆ W W0LT[օפإ𴢎 O8包ԥ卅 S o[LZ0 [q}` S S` S H Shԝ"` h SԪȱԨLEX [ȥՑ` |SԍՍLD```` jh qSr}դԍ`H Ge P󥋅 ehȱȱȱȱ#0eeL+\ h " s}]Lp\" =]Hhɛ hh`$0 t#ȱȄ {l樤 Q klL\ Q cl ,]t}5 =]H jhhɛ& {lL\h Qک` D`Lf hHHHH ~Vhhhh0 ذ: ۩҅ VL]H ]u}򈊢 Sh Vɛ,`8`򊅾ɛ ,Ȅɛž,ȱɛ`] q ]LutP#v}L^aZVp |R Sƨ$0! ةH ^h0 7S0֤ ^LG^L^į #ew}樂į ^Lu^ tƨL]L]  ^`)L{l Sƨ 7S ݥ h    x} _  _ _ em~a ha _La^HH Shhƨ$$  7S 8֍ L_ h y}0)Y'0 hHD Qh) 8庨Ƚ) ` .`8@ 8    _ _ saL^  z}`8!0``樤 `@m5 9i`00 ?`` _, e`` ` _ {} {l` `` hhL^`L` m <` [`hhL^ h 0*  @` h`` I` ```+|} -  ````$  ``` @` h``  @`  I` ```  [``  {l`   }}  h`` aHaH` aHaH`               k`o``x`}``~}```````Sa```@a``````4a`/a9a` t qS t8K nԅ n` S bLT b P b FLN}bLe lŅń`H) {lh t` Geħ-H Sh lLb qSԅħ qSԅՅ` }Q0Ů ŭ8`` t b P b c D Q QLc utLe QcƯ00 FcL2cei}`毤Hɛ) {lh` vc Vc L{l ci vc H vc vchȱȄ cğ` dRFH}h d dS d {lLc d) -c Vcɨ dLd6 Rƨ إ󅕥 VcLd d" {l} d {lƯ" {lLd8N -c d@Š) HI pcLd樤ħ`hh`J -cLsc g cV H }g g SԠ g Dکթ@} jh SԠ gh d% Ue ofŻ h`H ghȑȑʊȑ` Ge qSՅԅ PhhL~P >e h}` gLd gCAŻ gH %S U S gh U 8` U08` g e<` h g0 e " 1'`} h h pg ȱ` >e h jh l pg Q0 Qh h h`LZE S jhLe`` of``Ȅ} S  of` d` g0 e h hԅՆ֩פğȱȄA%0 Q Q0 sgLyf hLyf`} вLyfLyf fLZE f tg VcLJi Q0 LtSTOPPED0 P Q0 Q Q Q0LsgL f |S}ԍՍ` g S  Jeԅ qSƳ jh`L!e` PȄ` g gŻ 󥸅``őŐ8` g}H gh`LP gLO``ƺ`౐ƺ``䉐䈐`)}iiРфLt` SLEX}ѩ f0- (эѠL.e tSdхԩ ni(1i#}斪0, {l Vc Q0 |i i ci tLjEՈ ئ i` AT LINELVcBREAK KEY ABORMEM FULVALU}TOO MANY VARSTRING LEREAD, NO DATLINE#/VAL > 3276INPUT/REA DI EXPR TOO COMPLE OVERFLO NO SUCH LINE NEXT, NO FO}LINE TOO LONLINE DELETERETURN, NO GOSUBAD LINNOT NUMERILOAD, TOO BIFILE NOT SAVE FIL'USING' FORMA'USING' }TOO BI'USING' TYPDIM MISMATCTYPE MISMATCINPUT ABORNESTINPLAYER/MISSILE NUMBEPM GRAPHICS NOT ACTIVFATAL SYSTEM} ERROR!! END OF 'ENTER!UNIMPLEMENTED IN THIS VERSIO΁FILE ALREADY OPE΂BAD DEVICŃOPEN FOR WRITE ONLلBAD CMD FOR DEVICŅFI}LE NOT OPE·OPEN FOR READ ONLوEND OF FILňTIMEOUԍSCREEN POSITIOΐDEVICE DONE ERROғOUT OF ME͠DRIVE TOO MANY FILEӢDISK F}UL̥FILE NAMŧPROTECTED FILũDIRECTORY FUL̪FILE NOT FNīINVALID POIN {l l tL-tH lK@0%hɛK l}L0tGHFH`L tLh lLjE l`H t t thJKLM m`H lhH t t -t} 9}} Lh m eh`LZE h l 8倝偝 t t -t t󥃅} t -tLut t mH thLm mH thJKԝKսM |R u t t "u QL-t t tHH thh` !#$Lm }Qک l kl D l t tɈ utLtL3t t tL-t tLxpLt& @nLM t tNLt t qS tԝL՝M qS tԝN%}LEn t |SԦL~l t pp -tLt n n IH* tL-t t |S t՝EԝD |S t՝IԝH` tƨ _7 Sƨ҅}0 9oLn 7S ݥ؅ԥمթ 9oؤ Io @oLn` Go t -t`H thHI` tn SӅԅՅ҅  9oJLo} 7S ݩ 9o85/ԥեؤ Ioԥ @oԥեҥ SL]o h h` SHH SHH UrԅIꅣ0;hehhe}hLOhh8墅hh8墅LdP`  H SheԪpLEX h S)4LEX QLt t tL}t \bLf SH |S H |SheԨh` h S Hҩ |ShHԝ |S H |Shheԝ` |SԅUՅV S}ԅT` |Sԍ` p l JK tL-t r ut |SQq)I qL-tS: pL~l qqLam qqLmHq}h q -t`C:H lhKJ tLQ p lLn q,q,qLT q,q,qLTLT S)x`- r">x.|},Ԏ/o`"/Ѝ,`),$ Jix` rLr, ` h SH) 1Uh)`H)xr.|r/}h` 0? S` S rԅLIX r frH r ShH)) ԝФh` UrH CrȄhh)/.H0}-/-.) -/h`ሱ-/-.Ls rH) r H ShԨh` h =r Cr}` rH r80hH)h)`|r0 Ls--- ` r fr r rH rhM.` TԆԪ))}Ԣ))ઽ9tLTLT t 0` h t0`ɀ LD`Ɉ ut tLh] u}t+ hL]E t Lt tC` qS`IHEDB V`HH Shh LS r utƷ`t }{l`YDAER` 4SԅՅ֦󅗄``8`$)ԩeu (ې`)8@0+̪}Յ)e)e ݦ `F ݢu `ڢ ڰɠu @ݢ F I`U9>`D'RFuCU?b}9dYdg@W2@?tS)%@)@0)%ԅԢ ޢ ڰ9 @ݰ. ڰ" fڥԅԥ} u (`8`0?i (۩ ݢw `ڢ ڢ ݢ (ۢ `ڢl } fƢ ݥ#8@ji@)j `@0 B 8`8?0gP0YJJJJ)}ywe0C)weweJJJJwewe0)weweԥ` (2#AdAUSL=Ad/@V` A@ *D:GO0B@@ #- I/O ERROR-@0-}0I=A0/I=A2/)#@1- #I=A8/&@*D2:GO- B'faj } }  } } !"#$%&'()*+A,-. }/0123456789:;<=> }?@ABCDE@F@G@H@I@J@K@L@M@N }@O""PQINFO 4/19/83 COPYRIGHT CDC*R1A=AU/B -* AP8B@HA8-Press }Π to continue.7  7, AP'3+31 AP47)9BA(A($-ON '3-OFF }69)O B-"B@r@#=-H E L P I N D E XOB@H@Gv- 1. KEY USAGE)B@H@c }H-2. USING THE CALCULATORZB@H@yv-3. RULES OF THE QUIZ0B@H@0-4. SELECT A PROBLE }MF  +B@HAF-5. RETURN TO PROBLEM &@1B@rA51-CHOOSE AN OPTION -> F } 71 AR$72. A`1973C ApF, 74R09 7) AP,635*!* }" AQ (R0&, 6 AQZ B-_] B]-$The following keys will be available# everywhere u }nless otherwise noted:dVB@H@28-TO: PRESS:DA@BVCA@Bn`B@H@H }`-Continue ........ Π" Review .......... ̭ҠxbB@H@db-Access Data ..... } ̭Ġ" Question/Help ... ̭Ѡ`B@H@`-Return to INDEX . ̭ " Exit }lesson ..... ̭ؠ{B@HA9-Turn Sound ON/OFF ̭ӠKB@$A(_- SOUND IS NOWi AP }{B@$AR}C-A=@4/CTRL-A=@4/ means to press the letterUB@$A`}- while holdi }ng the CTRL key down.2  AP7*7% AP(2 ASz B-\ B'-TO USE THE CALCULATOR }:3B@$\-!First, locate the +, -, *, /, andHB@2H-"^ keys in the right quarter of the keyboard }._B@V_-Then find the parentheses signs$ above the 9 and 0 on the top row of_B@r_-!the ke }yboard. To type these signs" you just hold down the SHIFT key.JBAD-Now try typing the expression: }(3+5*2)/4JR0GR0@4!B@2A 1-A=A%/=BA#G-->VB@2A#R0 +BA }617; AP>V7 (3+5*2)/4Aa= R0&!:-!No. Press Π to try again.=A>-Not qu }ite, but let's continue. Press Π.A? 7*7 AP$3. A`1? Aa  A`p }9BA69-"Good. Press Π to continue., 7*7 AP,3Aa B-[ B }[- Also, you can make superscripts.$ Locate the ^ key. Shifted * is theTT-" exponent key ^. Your first p }ress enters superscript mode. AfterOO-! typing the superscripted numbers (the exponent) the ^ key alsoT( }- returns back to normal mode.4B@T-For example, to write 24=BA@w-131BA@ }=-*3.1$_*- type 24, then ^13^, then *3.1.6BA_-!Try typing some superscripts now.._--" Pre }ss Π when you are done.9BA6C-->UB@2A6[R0_ 87*7APB8 B-B@r }8-CALCULATOR FUNCTIONSLcA@!CA@-B@$c-Addition ........ + Subtraction .. }... -VTT- Multiplication .. * Division ........ / Exponentiation .. ^`PB@rP-Absolute val }ue .. ABS( ) Square root ..... SQRT( )jbb- e to Xth power .. EXP(X) Log base 10 ..... LOG( ) Natura }l logarithm LN( )tOBA O-Sine ......... .. SIN( ) Cosine .......... COS( )~GG- Tangent ........ }. TAN(X) Arctangent ...... ARCTAN( )?+- X degrees ....... X ̭Ϡ5 AP? APb B-g }YBA#- INTRODUCTION/B@2Y-"The main purpose of the quiz is tolVV- see if you can answer class }ical& physics problems correctly. A secondvMM-% purpose is to see whether you really understand the problem. }`B@`-!The amount of information you re-# quest indicates to some extent howD,-! well you understan }d the problem.6 APD7AP B-oB@V@7-INFORMATION ABOUT THE QUIZCB@$o- }$Each problem consists of four steps:[B@@[-1. Description of situation," 2. Question about the situ }ation,AA- 3. Request and receipt of more information,RR- 4. Computation of the problem# an }d evaluation of your answer._B@_-You start a problem by reading% the situation. Then you are asked a }V- question about it.*BA(V-$The description of the situation hasSS-! not provided all the informat }ion" necessary to answer the question.gO-% You must decide what information you need to work the problem.Y  }APg7Ap B-_B@_-"You will be given some cash to buy! this data and will be char }ged $2VV-$ for each item that you request. To" request the data that you need toVV- work the problem, you } press the& ̭Ġ key. You will see a ProblemVV-" Information display, which allows$ you to specify items }of information W!- that you wish to see.-B@W-"Word your requests for informationKK-" as simply as } possible and request only one item at a time. `BA `-"Although you may request up to six" pieces of i }nformation, do not re-*SS- quest anything that you do not$ really need as you will have to pay4+- for it. } AP+7ApU9 B->`B@`-"The Formulas and Constants display" lists formulas and cons }tands thatHHH-% can be used for working the problem. The list costs $5.R_B@H_-After you have recei }ved all the$ information you need to compute the\LL- problem, a calculator will be available for you to work }outfRR- the answer. Then you type the# answer at the 'ANSWER ->' point onpSS-# the screen. Your answer is }evalu- ated. Note that there is a twoz[[-% percent leeway for rounding off your& answer. If your answer is i }ncorrect,S- you are charged $5.+BA`S- To get started let's try an easy,,-! sample problem. Pres }s Π.,  7 AP,3+3As 7 Aq5R0 -0I=A0/I=A2/)#@1 }- #I=A8/&@. D2:PQINFO1 B'f Fs 3h R  S0ੀ S0֠ـ`Lw}} }} !"#$%&'()*+A,-.}/0123456789:;<=>}?@ABCDE@F@G@H@I@J@K@L@M@N}@OPR0B=I=A0//* PQMENU!!4/11 COPYRIGHT (C) 1983 CDC] R0R0R0R0!R0'R}0-R03R09R0?R0ER0KR0QR0WR0]R0Q R0R0R0R0!R0'R0-03R09R0?R0ER0}KR0QR0W R0R0R0R0!R0'R0-R03R09R0?R0ER0KR0QR0WR0K R0R0R0R}0!R0'R0-R03R09R0?R0ER0KR0K R1R1R1R1!R1'R1-R13R19R1?R1ER1KR1}K R1R1R1R1'R;/0;/3R;/0;/?R;/0;/KR;/0;/KR;/0;/R;/0;/'R;/0;/3R;/0;}/?R;/0;/KR;/0;/lR1R0@( @0.B6-H#A@Z#A@l#A }2B@H2-РҠϠ ̠Š͠ɠΠĠŠؠ>B@@1>-!1.Car (sample) 6.Plane to Cuba:}B@@U:-2.Cannon on cliff 7.SatelliteAB@@yA-$3.Falling object 8.Turbine and ball?B}@A?-"4.Cannon in field 9.Mass on spring-B@A'--5.Block on planeR0@9R0R}0 0B@2R0&@$R0U=;//R0&-$+ ;/R0&@(- *DONE*+}R0@90BAvR0&@$R0U=;//R0&-$+ ;/R0&@(-} *DONE*+ AB@AEA-$ ?B@AS?-You have c}ompleted  problems. 2B@Aa2- You have $ left.(@B@Au@-#Pick a problem or pres}s ̭Ѡ ->- 7AU751*69AQe< R0D=/F1#A #A'#A1 A|}* INDEX HELP5 B-#A )#A5#AAB@@#A-$From the PROBLEM INDEX you may} chose//-$ any of the problems to try next or---" to review. To choose a problem,..-# press the numb}er of that problem.AB@@cA-$When you have completed this lesson,$$- press ̭ؠ to exit.A }B@@A-$To return to the index page from any00-% point in a problem, press ̭ .=B@A }Q=- For more help, press Π or**- press ̭Ҡ for the Index. APAUSE7AP }3AUp R0 A-0I=A0/I=A2/)#@1- #I=A8/&@. D2:PQMEN }U1 B'f R  S0ੀ S0֠ـ`Lwj}} }} !"#$%&'()*+A,-.}/0123456789:;<=>}?@ABCDE@F@G@H@I@J@K@L@M@N}@O!!* D2:PQPROB6--PLANE TO CUBA!!4/19 COPYRIGHT (C) 1983 CDC] R0R0R0R0!R0'R0-R03}R09R0?R0ER0KR0QR0WR0]R0Q R0R0R0R0!R0'R0-03R09R0?R0ER0KR0QR}0W R0R0R0R0!R0'R0-R03R09R0?R0ER0KR0QR0WR0K R0R0R0R0!R0'R}0-R03R09R0?R0ER0KR0K R1R1R1R1!R1'R1-R13R19R1?R1ER1KR1K R1}R1R1R1'R;/0;/3R;/0;/?R;/0;/KR;/0;/KR;/0;/R;/0;/'R;/0;/3R;/0;/?R;/0;}/KR;/0;/KR1secondsR0@!M%K)K-K1K5KAR0@aK(A`O NNR0^=/*#A}A0O>0&&&B'H#LO)NA)V#AA!BA3- North windEB@r@}'V- Chicago *]R1<~~<&R0@(0 @0GR100SR0@0] @0bB@}@0(- ,>B@d@BG-NYB@d@Pb-qB@H@U-W1B@r}@U;-EMB@d@`V-hB@d@hq-SgR1 UUUAA#B@q- @3DR}1PTTUUUUUUUUN @3gR1PPTTTUTA=AR/@BAi@y @31BA$@v=-Cuba@))}NAh)L0A A$(#V=(/0R03:R09=ENIL)ZNAA@@0'CAr@p }9BA@9K-;?/ kmN)dNAA@@p'CAr@p9BAR@cK-;?/ kmN)nN!}AA@@0'CA@@p9BA(@GK-;?/ kmN)x+BA@@#(-;?/ m/s+),BA"}(@q)-;?/ m/s,):BA`@%"-;?/-R10HH07 @3:))))vB@#}@=- What length of TIME does it takeOB@@s-for the PLANE to reach Cuba?v)gB@r1-$}The problem is to find theCB@r@g-time of transit of the plane5B@r@#2-from Chicago %}to Cuba.5)"ZR0;?/R0(@P.B@A1<"'+!&ER;/0Z- Right again!9TR0(@`"R&}0(@P0"'+!&9R;/0T-Right--in minutes!<RR0(A6"R0(@P0"'+!&9R;/0R-'}Right--in hours!?SR0(A"R0(@P0"'+!&9R;/0S-Right--in meters.B_ AU--T(}hat's not a possible?B@A9_-answer. Press Π.E'R;/0;/' A!$'I3 ;/B@)}AC3-Press Π.J  3 ATP)A B-M;/#&R;/04R;/0;/'> AU*}AlB@@@-#In this problem the pilot is flyingl-$ a plane straight east. However, aW--" +}strong north wind is pushing theW-" plane so that an observer on the\/-$ ground sees the plane traveling inS-,} a southeasterly direction.\- Y0-% The southward speed of the plane isY-! due entirely to the north -}wind;\0-% Its southward speed is equal to the\-$ speed of the north wind pushing onO/-$ it. Speed and .}distance give time.AB@ACO-Press:_0-% Π for general information_-' OR ̭Ҡ to c/}ontinue this problem.0  7)7R0# &0 AUuI B-M;/!)B@@I-0}ˠԠŮMB@@#7-The answer to problem 6 isM-  .jB@@G?-"To1} work this problem, all you needj-# to know is the SPEED of the NorthE0-% wind and the DISTANCE of Cuba SouthE2}- of Chicago.,B@Au,-Press Π.8  7R09 !7+ A .8 AV`!3}7A S)X2/-Distance Chicago-Cuba: ;?/ km2)]/,-Distance Cuba East: ;?/ km/)b0--4}Distance Cuba South: ;?/ km0)g.+-North wind speed: ;?/ m/s.)l2/-Easterly plane speed: ;?/5} m/s2)q2/-Angle Cuba South: ;?/ degrees2)v%"-Think about it a while!%){I(-There is no compone6}nt of windF- from that direction.I)E%-The plane is heading in anB- easterly direction.E)D,-!Sp7}eed of the airplane East or theA- wind North?D)))- )- )-x=v*t)8}-w=m*g)-  )- )< -m -1 *-*v. 8-1< 9};-=m -2 +-*v/ 8-2;)-v=r*a)- ))- T=2 :}l/g)7- RADIUS=6.4*10 '-6+ 4-m7)-    ))- L = I*w = r*p);}-r=d/2)))[ -a -2 ,- b0 :-2> K- cO X-2[) <}Ad#AY  Ad AC Ad0AC Ad@AC AdPAC =} AC  Ad`#AY0! AdpAC"R1VERT& AC# AdAC$R1>}HOR& AC%!R1TRANSIT !AC&R1CUBA AC'!R1CHICAGO !AC( A?}C* Ad#AY@+ AdAC , AC4 Adp#AC5 Ad@AC6@} Ad AC7 AdPAC8 ACp##24,156,194,255,255,194,156,24 R1DIST& ) A}R1LENG& )  R1FAR )R1WEST& ) R1W )R1EAST& ) R1EB} )(R1NORTH& )) R1N )2R1SOUTH& )3 R1S )<R1SPE& )=C}R1VEL& )>R1RATE )?R1FAST )FR1WIND& )G R1AIR )PR1AIRD}PL& )QR1PLANE& )ZR1DIR& )[R1HEAD& )\R1SLOPE )]R1AE}NG& )-0I=A0/I=A2/)#@1- #I=A8/&@/ D2:PQPROB62 B'fwsh R  S0ੀ S0֠ـ`LwG}H} I}J} !"#$%&'()*+A,-.K}/0123456789:;<=>L}?@ABCDE@F@G@H@I@J@K@L@M@NM}@OPR0B=I=A0//* PQCALC - CALCULATOR!!4/19 COPYRIGHT (C) 1983 CDC] R0R0R0N}R0!R0'R0-R03R09R0?R0ER0KR0QR0WR0]R0Q R0R0R0R0!R0'R0-03R09RO}0?R0ER0KR0QR0W R0R0R0R0!R0'R0-R03R09R0?R0ER0KR0QR0WR0K R0RP}0R0R0!R0'R0-R03R09R0?R0ER0KR0K R1R1R1R1!R1'R1-R13R19R1?R1Q}ER1KR1K R1R1R1R1'R;/0;/3R;/0;/?R;/0;/KR;/0;/KR;/0;/R;/0;/'R;/0;R}/3R;/0;/?R;/0;/KR;/0;/ B-0B@@10-C A L C U L A T O ROB@dAg5S}-Press ̭Ҡ to leave.AB@cO- -> iB@@@`%-A=A$/7B@@@cG-A=A$T}/YB@@yi-A=A$/&CR0@4R0'B@@@c-R01 77?R0&C 3AP4U} R1R09 A`. R09R0R0E=/R0.R;/0@K 0R1:?/$40+29. AQV}15AR0@K AY"AYR1:?/R0&7.AR40+29AR4A+2W}ZAS# 7R0@ AT(>R0H=()+-*/^??/"'R0'1 AT4> AQO-- LITERALP X}R1ZR1:?/d!!.50*69/+3.AR@i R0&R1 ARxC R0&R;/0D=/R0' AQCPICY}KED OUT ENTIRE LITERAL R1CR1:?/5A*6Z& AS0)1R0&9R1C AS& R09&PICKED OUT ENTZ}IRE LITERAL 7ABSR0 AT7SQRTR0 AT 7EXPR0 AT 7LOGR0 AT[} 7LNR0 AT 7SINR0 AT# 7COSR0@# AT# 7TANR0@# A\}T&7ARCTANR0@& AT" !R0 AY&!!-- IS OPERATOR UNARY MINUS?'" ##+;/"]}R0@* R0R1, R0;/. AY1;/";/AX6#@AY; R0'@;/#^}AQH-- ELSE PERFORM OPERATIONJ R0;/R0L !"R0' R0;/M"'AUAUAUAU_}AU AU%AU0AU5AU@AUEAUPAUUAU`AUeAUpAUuAUO AT |`}R;/0&)R;/0')R;/0%) #R0)R;/0()R;/0$)R;/0U=/) !a}R0)R;/0S=/)R;/0P=/)R;/0R=/)R;/0Q=/)R;/0M=/)R;/0K=/)##Ob}V(VP)=SIN(SS)/COS(TS):RETURNR;/0M=/(K=/)R;/0J=/)R;/0(@W)WyP))R;/0')- R0&c}"@#R0@- AY R;/0 AQB@@y %  %-I don't understand.%'d}-=;/'BAv@y(- Press Π.*  7R0& ,7AP. AY0p<<-e} ERROR _=/ OCCURED AT LINE _=@/z  AP-0I=A0/I=A2/)#@1- #If}=A8/&@. D2:PQCALC1 B'f֠ـ`Lw8u"aq} r} s}t} !"#$%&'()*+A,-.u}/0123456789:;<=>v}?@ABCDE@F@G@H@I@J@K@L@Mw}@N@OP""* D2:PQPROB5--BLOCK ON PLANE!!4/19 COPYRIGHT (C) 1983 CDC] R0R0R0R0!R0'x}R0-R03R09R0?R0ER0KR0QR0WR0]R0Q R0R0R0R0!R0'R0-03R09R0?R0ERy}0KR0QR0W R0R0R0R0!R0'R0-R03R09R0?R0ER0KR0QR0WR0K R0R0R0Rz}0!R0'R0-R03R09R0?R0ER0KR0K R1R1R1R1!R1'R1-R13R19R1?R1ER1KR1{}K R1R1R1R1'R;/0;/3R;/0;/?R;/0;/KR;/0;/KR;/0;/R;/0;/'R;/0;/3R;/0;|}/?R;/0;/KR;/0;/AR1secondsR0MK#K'K+K7R0@`A(A` NFR0^=/$#A}}A*O80&&&<'B#F)NA)`#AA'AA@39CA@~}KCA@]CA@3`)N@)N R09!0A@9)NC0@.'@/(}GKN)Z*B@d@i'-;?/ kg*)d)n/BAD@q,-;?/ degrees/)xiAA@p}'CA@`9CA@eECAWCA@iCA@%}*BA@9'-;?/ m.}*)*BA@U'-;?/ m.*)*BA@@q'-;?/ m.*))))@B@@}@-#How long does it take for the BLOCK8B@@5-to slide down the PLANE?8)lB@r@7-}The problem is to find theIB@r@l-time for the block to slide/B@r@#,-down the plan}e./)"R0;?/'R0(@P,B@A16"'+!&R;/08N%-Did you consider friction?7B@}A9N-Press Π.9; &*R0S=U=%;?/(.%M=;?/////-;R0(@P:"'+!&R;/0;S}!-OK. Your answer is for3B@A9S-radians and not degrees.<;-R0S=U=%;?/(.A %M=;?/////};R0(@P="'+!&R;/0>P'-You've used the wrong units.9B@A9P-Press Π.@} AUBR -That's not a possible2B@A9R-answer. Press Π.ER;/0;/' AH }  J L3ATP^) B-M0 ;/#R;/0#R;/0;/'- AU0mB@@}B-%You find the time as follows. First,m-# compute the speed of the block atM,-! the bottom of the inclin}e usingM- conservation of energy.fB@@U:-With this information and thef-$ initial speed, yo}u can compute theX.-# average speed of the block on theX-" plane. Then you use the average\/-$ speed a}nd the distance traveled to\-% compute the amount of time it takes<,-! for the block to slide down the<- } plane.#B@AC#-Press:_0-% Π for general information_-' OR ̭Ҡ to continue t}his problem.  7) 7R0  AUu B-M8 ;/!B@@8-Ҡˠ}ԠŮMB@@#7-The answer to problem 5 isM-  .kB@@G?-"To work }this problem, all you needk-$ to know is the LENGTH and ANGLE of- the plane.,B@Au,-Pre}ss Π.  7R09 A!7A & AV`Mgg"AW AW%AW0AW5AW@AWE}AWPAWUAW`AWeAWpAWuS)X*'-Mass of block: ;?/ kg*)]1.-Weight of block:} ;?/ Newtons1)b/,-Incline angle: ;?/ degrees/)g-*-Plane length: ;?/ meters-)l-*-}Plane height: ;?/ meters-)q,)- Base length: ;?/ meters,)vH*-The block height is the same asE-} the plane height.H){?'-Good question! The plane is<- stationary.?)D%-Answer the problem for the}A- non-friction case.D).+- That's the point of the problem..)S+- Gravity is a constant found withP-} the Formulas and Constants.S))&-The block starts from rest.))- )- )0-x=a*}t -2# --/20)-x=v*t))- )-F=u*N)-w=m*g) -}_)- )M-v=(v -1" --+v1 ;-2? J-)/2M)L -v }-f ,-=v0 :-i> B L-2 -+2a*x)))'- g=9.8 m/sec $-}2')A-KE=m*v  -2$ 1-/2ec5 >-2A)))-PE=m*g*h)R1BLOCK} AYPR1OBJ& AYPR1MASS& AYPR1PLANE AYUR1SLIDE }AYU!R1INCLINE !AYUR1WEDGE AYUR1RAMP AYU R1HYPOT& } AYU R1BASE AY`! R1BOTTOM  AY`"R1HOR& AY`$R1ANG& }AC%R1SLOPE AC&!R1INCLIN& !AC(R1FRIC& AC ) R1SMOOT& } AC * R1MU AC + R1RESIS&  AC -R1ACC& AC.R1ACEL& }AC0R1GRAV& AC1 R1G AC4R1SPE& AC5R1VEL& AC}6R1RATE AC7R1FAST AC9 AYAC: AC>R1WEI& AC}? AYAC@ ACC AYACD AYACE ACH AYA}CI AY$\R1HEI& )]R1VERT& )^R1HIGH )_R1TALL )` R}1TOP )fR1LEN& )gR1DIST& )hR1WID& )i R1FAR )jR1S}IZE )p8,20,34,65,130,68,40,16-0I=A0/I=A2/)#@1- #I=A8/&@/ D2:P}QPROB52 B'fj9x!}!} !}!} !"#$%&'()*+A,-.!}/0123456789:;<=>!}?@ABCDE@F@G@H@I@J@K@L@M@N!}@O* D2:PQPROB7 - SATELLITE!!4/19 COPYRIGHT (C) 1983 CDC] R0R0R0R0!R0'R0-R03R0!}9R0?R0ER0KR0QR0WR0]R0Q R0R0R0R0!R0'R0-03R09R0?R0ER0KR0QR0!}W R0R0R0R0!R0'R0-R03R09R0?R0ER0KR0QR0WR0K R0R0R0R0!R0'R0!}-R03R09R0?R0ER0KR0K R1R1R1R1!R1'R1-R13R19R1?R1ER1KR1K R1R1!}R1R1'R;/0;/3R;/0;/?R;/0;/KR;/0;/KR;/0;/R;/0;/'R;/0;/3R;/0;/?R;/0;/!}KR;/0;/HR1 kilometersR0M"K&K*K.K2K>R0@H(A` NNIR0^=/$#A!}@*O80&&&<'B#FI))N2R1   A=@4/A=@4/ * DBA(@(N @!}3(R1( * )( @3)R1 * & @3))KR0ARR0@Y% AQ7!}BA`@IH- satelliteK)6 AC&C&&#C&)C3C&&6)e0A,R0A8&@%!}%M=/ER0@8&@%%K=/I?S AQW?a AQe ? )Z0BAv@9--;?/ meters/s0)!}d*BAv@c'-;?/ kg*)n=B@r@:- One orbit: ;?/ seconds=)x)))!})))yB@@=- What is the RADIUS of the satel-OB@@y-"lite's orbit (i.e. the di!}stance to4B@A1-the Earth's center)?4)eB@r1-The problem is to find theCB@r@!}e-radius of the orbit of the*B@r@#'- satellite.*)"ER0;?/R0(@P.B@A1!}<"'+!&ER;/08R"-Sputnik never had it so4B@A9R-good! Press Π.9"R0%A!}"R0(@P:"'+!&R;/0;Q-That's the answer.B@A9Q-in meters. Press Π.A!} AUBR -That's not a possible2B@A9R-answer. Press Π.E!R;/0;/' A!}!J  3 ATP)A B-M;/#&R;/04R;/0;/'> AUAiB@@A-$!}In this problem the force of attrac-i- tion between the Earth and the^0-% satellite equals the product of the!}^-& satellite's mass and its centripetal- acceleration.oB@@cB-%You find the force using !}Newton's lawo-% of universal gravitation. Use thisR0-% force and the orbital speed to findR- the radius!} of the orbit.#B@AC#-Press:_0-% Π for general information_-' OR ̭Ҡ to con!}tinue this problem.0  7)7R0# &0 AUuI B-M;/!)B@@I-Ҡ!}ˠԠŮMB@@#7-The answer to problem 7 isM-  .lB@@G?-"To w!}ork this problem, all you needl-% to know is the PERIOD of the orbit.,B@Au,-Press Π.8 !} 7R09 !7+ A .8 AV`S)X52-Orbital speed: ;?/ meters/second5)]2/-Mass !}satellite: ;?/ kilograms2)b0--Orbital period: ;?/ seconds0)gI/-$That's a constant, found in Form!}ulasF- and ConstantsI)lS--"Consider the center of the mass toP- be at the Earth's center.S)q63-(W!}ork that out from the first principles.6)v){)))- ) -)-x=v*t)Y-!}F=(G*m  -1$ .-m2 <-2@ K-/rO Y-2 -))))C-G=!}6.7*10 $--11( 3-Nm7 @-2C)-f=1/T)))'- g=9.8 m/sec $-2')!}5- Me=6.0*10 $-24( 2-kg5)))7- RADIUS=6.4*10 '-6+ 4-m7)-!}r=d/2)))O-E=-G*m  -1$ /-*m3 =-2A L-/2rO) Abp0,!}0,0,24,24,0,0,0B AbEACC AbUAb0D AbeACE AbpACF Abu!}ACG AbAb@H AbAC I ACV AdACW Ad AC!}X Ad0ACY Ab` Ad eR1SPE& )fR1VEL& )gR1RATE !})hR1FAST )oR1MASS& )pR1WEI& )qR1HEAVY )yR1PERIOD )!}zR1TIME )~R1GRAVITY ) R1G )R1GRAVITA& )R1RADI& )R!}1DIAM& )R1WIDTH )R1FORC& )R1ACC& ) R1SAT& ) R1SP!}ACE& ) R1CAPSULE ) R1CRAFT )R1EARTH )R1WORLD )R1!}TERRA& )R1CENTER )-0I=A0/I=A2/)#@1- #I=A8/&@/ D2:PQ!}PROB72 B'f j]%}%} %}%} !"#$%&'()*+A,-.%}/0123456789:;<=>%}?@ABCDE@F@G@H@I@J@K@L@M@N%}@O""* D2:PQPROB8--TURBINE / BALL!!4/19 COPYRIGHT (C) 1983 CDCKR1 radians/sec!R0@%M)K-K%}1K5KAR0@pK(A` NN@ R0^=/#AA$O20&&&6'<#@XXP=PMADR(K1)%}:POKE 705,116:PMWIDTH K1,K1:FOR I=P+Y TO P+Y+7:READ T1:POKE I,T1:NEXT I*R1<~~~< 000<~~~< R0* @0cSR1 p%}p <A=AT/gA=A'/<0A=@1/A=@1/YR0c @02"R1~(R%}02 @02"R1x~ff~(R02 @0G7R1A=A'/A=A'/<8=R0G%} @0z"R1>>?.R0@8 @0dR1 | pR0@z @%}08"R1||8 .R0@!8 @0)!)N@NA!){$AB!N%}AP3BA@@>-  PBA@H[-mBA@Vx-  {))NA) R%}0R0R0c V=/#BA@@)-  ;BA@HF-XBA@Vc-  c V=/#%}BA@@)-;BA@HF- XBA@Vc- j V=/#R09%BA@@%}0-BBA@HM-_BA@Vj-I R0&%R0&U=/&NAP'<@E+ %}F AQI/!)"R09?30, AQ/Z3BA@!0-;?/ radians/sec3)dSB@%}@Y*-;?/ kg-mG#@L=@/'@P-2S)n.BA&@A+-;?/ kg-m/s.)x.B%}A`@G+-;?/ kg-m/s.)+BA@5(-;?/ ms.+),BAg@A)-;?/ m/s%},)*BA@I'-;?/ kg*).BA@(+-;?/ meters.))SB@@A-$%}What is the NEW ANGULAR SPEED of theSB@@N,-!turbine after being struck by the>B@AK-b%}all?N)mB@r@7-The problem is to find theIB@r@m-angular speed of the turbine>B@r%}@#;-after colliding with the ball.>)"ER0;?/R0(@P.B@A1<"'+!&ER;/08%}K"-You study a lot, right?4B@A9K-Press Π.B_ AU--That's not a possible?B@%}A9_-answer. Press Π.ER;/0;/' AJ  3 ATP)A B-M%};/#&R;/04R;/0;/'> AUAoB@@A-$You can use conservation of momentumo-& in solvin%}g this problem. The changeZ+- in the angular momentum of theZ-' turbine equals the change in momentumE1-%}& of the ball multiplied by the radiusE- of impact.Z-0- Find the change in momentum ofZ-" the ba%}ll and the initial angularV+- momentum of the turbine; usingV-# these, compute the final speed of- %}the turbine.#B@AC#-Press:_0-% Π for general information_-' OR ̭Ҡ to conti%}nue this problem.6 A7)7%R0) ,6 AUuI B-M;/!)B@@I-%}ҠˠԠŮMB@@#7-The answer to problem 8 isM-  .gB@@G?-"%}To work this problem, all you needg- to know is the INITIAL ANGULARe,-! MOMENTUM of the turbine and theX-%}$ INITIAL and FINAL momentums of thee-ball.,B@Au,-Press Π.8  7R09 !%}7+ A .8 AVUS)X96-Initial angle speed: ;?/ radians/sec9)]\1-Mom. inertia turbine: ;%}?/ kg-mP#.@/L=@/'@Y-2\)b41-Ball's initial mom.: ;?/ kg-m/s4)g2/-Ball's &}final mom.: ;?/ kg-m/s2)l52-Ball's initial velocity: ;?/ m/s5)q30-Ball's final velocity: ;?&}/ m/s3)v)&-Mass of ball: ;?/ kg)){30-Collision impact radius: ;?/ m3)D(-Ask for the&} moment of inertiaA- of the turbine.D)K--"Speed of what? Angular of linear?H- initial or final?K)O&}(-Momentum of what? angular orL- linear? Initial or final?O)?+- You'll have to calulate that for<-&} yourself.?)2/-$The collision is completely elastic.2)-  )-  )N-F*t&}=m(v !-f% 0--v4 >-iB K-)N)L -m !-@1% 0-*v4 >-1&}B L-=@ -m !-@2% 0-*v4 =-2@)))0-F=(mv -2# &}--/r0)1-KE=I*w  -2$ .-/21)- )-  )-v=r*a)&}-W=Fos)- ))L -v -f ,-=v0 :-i> B L-& }2 -+2a*x)'- g=9.8 m/sec $-2')-    ))- L=I*w=r*p) Ab& }p0,0,0,24,24,0,0,0> Ab@Ab@ AbPAbB Ab`AbpD/R1ELASTIC & }%R0@/ ACF/R1INELAS& %R0@/ ACHR1RADI& ACJR1DIST& & }ACLR1LENG& ACN"R1DIAMETER "ACPR1SIZE ACR R1ARM & }ACT R1IMPACT  ACV#R1 COL&ISION #ACX R1MOMENT  ACZ AC`R&}1SPE& )bR1VEL& )dR1RATE )fR1FAST )jR1MOMENTUM )l R&}1P )tR1MASS& )vR1HEAVY )xR1INERTIA )zR1WEI& )~ R1MO&}MENT  AC!R1TURBIN& !AC R1WHEEL )R1BALL AC Ab&}R1ANG& AC AdAC AdAC AC AdAC Ad&}ACR1ANG& AC ACR1INIT& )R1START& ) R1OLD&} )R1BEGIN& )R1FINAL ) R1NEW )R1END& )-0I=A0/I=&}A2/)#@1- #I=A8/&@/ D2:PQPROB82 B'f$Xj*}*} *}*} !"#$%&'()*+A,-.*}/0123456789:;<=>*}?@ABCDE@F@G@H@I@J@K@L@M@N*}@O""* D2:PQPROB9--MASS ON SPRING!!4/19 COPYRIGHT (C) 1983 CDC] R0R0R0R0!R0'R0-R0*}3R09R0?R0ER0KR0QR0WR0]R0Q R0R0R0R0!R0'R0-03R09R0?R0ER0KR0QR*}0W R0R0R0R0!R0'R0-R03R09R0?R0ER0KR0QR0WR0K R0R0R0R0!R0'*}R0-R03R09R0?R0ER0KR0K R1R1R1R1!R1'R1-R13R19R1?R1ER1KR1K R1* }R1R1R1'R;/0;/3R;/0;/?R;/0;/KR;/0;/KR;/0;/R;/0;/'R;/0;/3R;/0;/?R;/0*!};/KR;/0;/LR1cm/secR0@ M$K(K,K0KBAC@#J- T @3k-*+} ;?/ cm.n)dGB@A@A!-;?/3B@A@ID- dynes/cm.G)n2BA@A/- ;*,}?/ grams2)x))))))QB@@?-"What is the MAXIMUM SPEED attainedQB@*-}@R/-$by the block as it oscillates on theAB@AO-table?R)kB@r@7-The pro*.}blem is to find theIB@r@k-MAXIMUM SPEED of the block>B@r@#;-as it oscillates on the t*/}able.>)"ER0;?/R0(@P.B@A1<"'+!&ER;/08H-It's easy, isn't it?1B@A9*0}H-Press Π.B_ AU--That's not a possible?B@A9_-answer. Press Π.ER*1};/0;/' AJ  7) ATP= B-;/#"R;/00R;/0;/': AU=jB@*2}@@-#The mass is drawn back and releasedj-" from rest. At this position the[/-$ mass has a certai*3}n value of poten-[-$ tial energy and NO kinetic energy.b-5-% At this point of maximum speed, theb-% m*4}ass is in the equilibrium position+&- with NO POTENTIAL energy.+-L/-$ Use conservation of energy to find*5}L- this maximum speed.#B@AC#-Press:_0-% Π for general information_-' OR *6}̭Ҡ to continue this problem.6 A7)7%R0) ,6 AUuOM B-;/!/B@@*7}@O-ҠˠԠŮMB@@#7-The answer to problem 9 isM-  .mB*8}@@G?-"To work this problem, all you needm-& to know is the initial displacement,S2-' the mass o*9}f the block and the stretchS- constant of the spring.,B@Au,-Press Π.8  7R09*:} !7+ A .8 AVUS)X2/-Initial displacement: ;?/ cm.2)]30-Sprint constant: ;?*;}/ dynes/cm.3)b-*-Mass of block: ;?/ grams-)g,)-Period of oscillation: ;?/,)l/,-Frequenc*<}y of oscillation: ;?//)q+(-Consider it to be stationary.+)v0--"Consider an ideal massless spring.0){(%-*=}The table is frictionless.())&-The block starts from rest.))@$-Calculate that from other=- cons*>}iderations.@)- )- )-v=a*t)-x=v*t) -)- *?})M-v=(v -1" --+v1 ;-2? J-)/2M)- T=(1/2)m/k)))-*@}f=1/T)H-KE -i ,-+PE0 :-i> H-=<-KE -f ,-*A}+PE0 9-f<)))0-KE=kx -2# --/20)-PE=m*g*h)))-*B}w=2*f) AbpAA255,255,255,255,255,255,255,255,0,106,149,149,149,149,106,0> AbAbp@R1DIS*C}P& ACBR1DIST& ACD!R1STRETCH !ACFR1LENG& ACH R1FA*D}R ACJ R1AMPLI&  ACL$R1 ELONGATION $ACPR1STIFF ACRR1*E}CON& ACT R1K ACV R1PERIOD  ACXR1TIME AC\R1FREQ&*F} AC` R1FRICT&  ACb!R1SMOOTH& !ACd R1MU ACf R1RESIS&*G}  ACjR1SPE& AC lR1VEL& AC nR1RATE AC pR1FAST *H}AC t"R1ENERGY "#ACv R1POTEN&  ACx!R1KINETIC !ACz R1ENERG*I}Y  AC| AC~R1WALL ACR1TABLE AC R1SPRING  AC*J}R1COIL AC ACR1BLOCK )R1MASS& )R1WEI& )R*K}1HEAVY )R1OBJECT )-0I=A0/I=A2/)#@1- #I=A8/&@/ D*L}2:PQPROB92 B'f(