›MODULE  ; Example 3›SET $B5 = $1BFF››; Note that this value is $4003 (the›; address of the byte following the›; first module) minus $2404, my LOMEM›; address.  Again, as in Example 2,›; adjust your values accordingly.››; First off, we have to tell this›; module where our globals are:››BYTE›  two = $4000, three = $4001,›  four = $4002››; Now, for this module's code:››PROC Main()›BYTE›  i, j, k››  i = two + three›  j = three + four›  k = two + three + four›  PrintF("i=%U, j=%U, k=%U%E",›         i, j, k)›RETURN››