45΅; R SIZΕRAΝARRAY€A€LEFT€RIGHT€LEVEL€ΩΨΪLEVEΜCOUNΤSORΤΑΒΓ@A3*Δ&Δ&Η&Ψ؁Ÿ@Ψ؁wZ Ψ@ @ @ @@&&*********** HEAPSORT ***********›&&****** by GREGG HESLING *******› a @%(Max. size/entry)€S6-P:+I:,&€&A,'+€%@,,a‚;$€,ƒ;€, ``Recursion devours RAM, up to 28% in this program depending on the "maximum size per entry"›f,„;$@,…;$@,†;$@,46„.G6„7$@,.V6„7@,.„\6….„f @PccLEFT$ and RIGHT$ will store the pointers, while LEVEL$ will be the "recursive variable saver"›d76‡-@:„7ˆ$@&@,,$AV%@:„7ˆ$@,,K‡"@0dThere is no left child›jjThe address of the current node is stored, then we make the left child the current node and go again›x6‰-P:ˆ'AV,26†7Š%@<Š%@,.>:‰,Z6†7Š%@<Š%@,.>:ˆ&‰$AV,h6Š-Š%@n6ˆ-‡x @ n"(‚7+ˆ&@,$€%@<ˆ$€,nARRAY$ is printed in sorted order -- left child, parent, then right child›#w76‡-@:…7ˆ$@&@,,$AV%@:…7ˆ$@,,;‡A6ˆ-‡K @ wFollow right leg without saving positions›'aaRestore the last saved position -- the parent with a left child -- and go directly to PRINT›(KŠ6Š-Š&@A6ˆ-@:†7Š%@,,$AV%@:†7Š%@,,K @02.(.(‹ records used&‹ records left7l(Entry: ƒ 6ˆ-@'ƒ436Œ-@?6Š-I @ lGo to recursive printing routine›;mmStore new string, then use a binary tree search to determine the new string's position and set pointers›<d 6-€$‹Ž-@€&6‚7%Ž,. * ŽB6‚7%@<%B:ƒ,,.ƒP6‹-‹%@d‹"@@UAfG‚7+‹&@,$€%@<‹$€,3‚7+ˆ&@,$€%@<ˆ$€,@ufFollow left or right branch?›EVVLeft branch. If there is a child, go to it. Else, save new entry at this point›F76‡-@:„7ˆ$@&@,,$AV%@:„7ˆ$@,,A @€O6„7<,.>:,w6„7%@<%@,.>:Ž&$AV, @UJWWRight branch. If there is a child, go to it. Else, save new entry at this point›K76‡-@:…7ˆ$@&@,,$AV%@:…7ˆ$@,,A @€O6…7<,.>:,w6…7%@<%@,.>:Ž&$AV, @UP‡ 6ˆ-‡' @eU36-ˆ$@&@6Ž-‹06-P:Ž'AV,3$YooChange line 55 to line 56 and type "55 IF COUNT THEN GOSUB 95" to see previous entries and their pointers›Zaˆ-@‹a(@:„7ˆ$@&@,,$AV%@:„7ˆ$@,,‚7+ˆ&@,$€%@<ˆ$€,_<5(@:…7ˆ$@&@,,$AV%@:…7ˆ$@,,9 ˆ<$€D2:HEAPSORT.BAS